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JavaScript: Find the second lowest and second greatest numbers from an array

JavaScript Function: Exercise-11 with Solution

Write a JavaScript function which will take an array of numbers stored and find the second lowest and second greatest numbers, respectively.

Pictorial Presentation:

JavaScript: Second lowest and second greatest numbers from an array

Sample Solution: -

HTML Code:

<!DOCTYPE html>
<html>
<head>
<meta charset=utf-8 />
<title>Find the second lowest and second greatest numbers from an array</title>
</head>
<body>
  
</body>

JavaScript Code:

function Second_Greatest_Lowest(arr_num)
{
  arr_num.sort(function(x,y)
           {
           return x-y;
           });
  var uniqa = [arr_num[0]];
  var result = [];
  
  for(var j=1; j < arr_num.length; j++)
  {
    if(arr_num[j-1] !== arr_num[j])
    {
      uniqa.push(arr_num[j]);
    }
  }
    result.push(uniqa[1],uniqa[uniqa.length-2]);
  return result.join(',');
  }

console.log(Second_Greatest_Lowest([1,2,3,4,5]));

Sample Output:

 2,4

Flowchart:

Flowchart: JavaScript function: Second lowest and second greatest numbers from an array

Live Demo:

See the Pen JavaScript -Second lowest and second greatest numbers from an array-function-ex- 11 by w3resource (@w3resource) on CodePen.


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Next: Write a JavaScript function which says whether a number is perfect.

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JavaScript: Tips of the Day

How to check whether a string contains a substring in JavaScript?

ECMAScript 6 introduced String.prototype.includes:

const string = "foo";
const substring = "oo";

console.log(string.includes(substring));

includes doesn't have Internet Explorer support, though. In ECMAScript 5 or older environments, use String.prototype.indexOf, which returns -1 when a substring cannot be found: 

var string = "foo";
var substring = "oo";

console.log(string.indexOf(substring) !== -1);

Ref: https://bit.ly/3fFFgZv