JavaScript: Count total number of 1s from 1 to N
JavaScript Math: Exercise-102 with Solution
Write a JavaScript program to count the number of times the digit 1 appears in 1 to a given number.
Example : 11, 1 appears 4 time between 1 to 11 [1->1, 10->1 ,11-.2]
Test Data:
(11) -> 4
(305) -> 161
(0) -> false
Sample Solution:
HTML Code:
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>JavaScript program to Count total number of 1s from 1 to N</title>
</head>
<body>
</body>
</html>
Solution-1
JavaScript Code:
function test(num) {
if (n<1)
return false;
var ctr = 0;
for (var i = 1; i <= n; i *= 10) {
var d = i * 10;
ctr += parseInt(n / d) * i +
Math.min(Math.max(n % d - i + 1, 0), i);
}
return ctr;
}
n = 11
console.log("n = " +n)
console.log("Total number of 1s from 1 to n: "+test(n));
n = 305
console.log("n = " +n)
console.log("Total number of 1s from 1 to n: "+test(n));
n = 0
console.log("n = " +n)
console.log("Total number of 1s from 1 to n: "+test(n));
Sample Output:
n = 11 Total number of 1s from 1 to n: 4 n = 305 Total number of 1s from 1 to n: 161 n = 0 Total number of 1s from 1 to n: false
Flowchart:

Live Demo:
See the Pen javascript-math-exercise-102 by w3resource (@w3resource) on CodePen.
Solution-2
JavaScript Code:
function test(num) {
if (num<1)
return false;
var result = 0;
for (var x = 1; x <= num; x *= 10) {
var temp = parseInt(num / x), remin = num % x;
result += parseInt((temp + 8) / 10) * x;
if (temp % 10 == 1)
result += remin + 1;
}
return result;
}
n = 11
console.log("n = " +n)
console.log("Total number of 1s from 1 to n: "+test(n));
n = 305
console.log("n = " +n)
console.log("Total number of 1s from 1 to n: "+test(n));
n = 0
console.log("n = " +n)
console.log("Total number of 1s from 1 to n: "+test(n));
Sample Output:
n = 11 Total number of 1s from 1 to n: 4 n = 305 Total number of 1s from 1 to n: 161 n = 0 Total number of 1s from 1 to n: false
Flowchart:

Live Demo:
See the Pen javascript-math-exercise-102-1 by w3resource (@w3resource) on CodePen.
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