# JavaScript: Count total number of 1s from 1 to N

## JavaScript Math: Exercise-102 with Solution

Write a JavaScript program to count the number of times the digit 1 appears from 1 to an given integer.

Example : 11, 1 appears 4 time between 1 to 11 [1->1, 10->1 ,11-.2]

**Test Data:**

(11) -> 4

(305) -> 161

(0) -> false

**Sample Solution:**

**HTML Code:**

```
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>JavaScript program to Count total number of 1s from 1 to N</title>
</head>
<body>
</body>
</html>
```

**Solution-1**

**JavaScript Code:**

```
function test(num) {
if (n<1)
return false;
var ctr = 0;
for (var i = 1; i <= n; i *= 10) {
var d = i * 10;
ctr += parseInt(n / d) * i +
Math.min(Math.max(n % d - i + 1, 0), i);
}
return ctr;
}
n = 11
console.log("n = " +n)
console.log("Total number of 1s from 1 to n: "+test(n));
n = 305
console.log("n = " +n)
console.log("Total number of 1s from 1 to n: "+test(n));
n = 0
console.log("n = " +n)
console.log("Total number of 1s from 1 to n: "+test(n));
```

Sample Output:

n = 11 Total number of 1s from 1 to n: 4 n = 305 Total number of 1s from 1 to n: 161 n = 0 Total number of 1s from 1 to n: false

**Flowchart: **

**Live Demo: **

See the Pen javascript-math-exercise-102 by w3resource (@w3resource) on CodePen.

**Solution-2**

**JavaScript Code:**

```
function test(num) {
if (num<1)
return false;
var result = 0;
for (var x = 1; x <= num; x *= 10) {
var temp = parseInt(num / x), remin = num % x;
result += parseInt((temp + 8) / 10) * x;
if (temp % 10 == 1)
result += remin + 1;
}
return result;
}
n = 11
console.log("n = " +n)
console.log("Total number of 1s from 1 to n: "+test(n));
n = 305
console.log("n = " +n)
console.log("Total number of 1s from 1 to n: "+test(n));
n = 0
console.log("n = " +n)
console.log("Total number of 1s from 1 to n: "+test(n));
```

Sample Output:

n = 11 Total number of 1s from 1 to n: 4 n = 305 Total number of 1s from 1 to n: 161 n = 0 Total number of 1s from 1 to n: false

**Flowchart: **

**Live Demo: **

See the Pen javascript-math-exercise-102-1 by w3resource (@w3resource) on CodePen.

**Improve this sample solution and post your code through Disqus**

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## JavaScript: Tips of the Day

**Shorten an array using its length property**

A great way of shortening an array is by redefining its length property.

let array = [0, 1, 2, 3, 4, 5, 6, 6, 8, 9] array.length = 4 // Result: [0, 1, 2, 3]

Important to know though is that this is a destructive way of changing the array. This means you lose all the other values that used to be in the array.

Ref: https://bit.ly/2LBj213

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