# JavaScript: Sum of all odds in a matrix

## JavaScript Math: Exercise-91 with Solution

Write a JavaScript program to calculate the sum of all odd elements in a square matrix.

Test Data:
([ [1, 2, 3], [4, 5, 6], [7, 8, 9] ]) -> 25
( [ [-1, -2], [-4, -5] ]) -> -6

Sample Solution:

JavaScript Code:

``````/**
* Function to calculate the sum of all odd numbers in a matrix.
* @param {number[][]} nums - The matrix containing numbers.
* @returns {number} - The sum of all odd numbers in the matrix.
*/
function test(nums) {
// Flatten the matrix into a single array
return nums.reduce((b,a) => [...b,...a], [])
// Calculate the sum of all odd numbers in the flattened array
.reduce((b,a) => !(a%2) ? b: a+b , 0);
}

// Test cases
// Test the sum of all odd numbers in the first matrix
nums = [
[1, 2, 3],
[4, 5, 6],
[7, 8, 9]
];
console.log("Sum of all odds of the said matrix: "+test(nums));

// Test the sum of all odd numbers in the second matrix
nums = [
[-1, -2],
[-4, -5]
];
console.log("Sum of all odds of the said matrix: "+test(nums));
```
```

Output:

```Sum of all odds of the said matrix: 25
Sum of all odds of the said matrix: -6
```

Flowchart:

Live Demo:

See the Pen javascript-math-exercise-91 by w3resource (@w3resource) on CodePen.

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