JavaScript Exercises: Count number of nodes in a Singly Linked List
JavaScript Singly Linked List: Exercise-3 with Solution
Write a JavaScript program to create a singly linked list of n nodes and count the number of nodes.
Sample Solution:
JavaScript Code:
class Node {
constructor(data) {
this.data = data
this.next = null
}
}
class SinglyLinkedList {
constructor(Head = null) {
this.Head = Head
}
add(newNode){
let node = this.Head;
if(node==null){
this.Head = newNode;
return;
}
while (node.next) {
node = node.next;
}
node.next = newNode;}
NodeCount() {
let ctr = 0;
let node = this.Head;
while (node) {
ctr++;
node = node.next;
}
return ctr;
}
displayList(){
let node = this.Head;
var str = ""
while (node) {
str += node.data + "->";
node = node.next;
}
str += "NULL"
console.log(str);
}
}
let numList = new SinglyLinkedList();
numList.add(new Node(2));
numList.add(new Node(3));
numList.add(new Node(4));
numList.add(new Node(5));
numList.add(new Node(6));
numList.add(new Node(7));
console.log("Original Linked list:")
numList.displayList();
var ctr = numList.NodeCount();
console.log("Number of elements in the said Linked list: "+ctr)
Sample Output:
Original Linked list: 2->3->4->5->6->7->NULL Number of elements in the said Linked list: 6
Flowchart:

Live Demo:
See the Pen javascript-singly-linked-list-exercise-3 by w3resource (@w3resource) on CodePen.
Improve this sample solution and post your code through Disqus
Singly Linked List Previous: Print a singly linked list in reverse order.
Singly Linked List Next: Insert a new node at any position of a Singly Linked List.
What is the difficulty level of this exercise?
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JavaScript: Tips of the Day
Shorten an array using its length property
A great way of shortening an array is by redefining its length property.
let array = [0, 1, 2, 3, 4, 5, 6, 6, 8, 9] array.length = 4 // Result: [0, 1, 2, 3]
Important to know though is that this is a destructive way of changing the array. This means you lose all the other values that used to be in the array.
Ref: https://bit.ly/2LBj213
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