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JavaScript join() Method: Array Object

Description

The join() method is used to join all elements of an array into a string. The elements are separated by a specified separator.

Version

Implemented in JavaScript 1.1

Syntax

join(separator)

Parameters

separator: Specifies a string to separate each element of the array. Default separator for the join() method is comma(',').

Example:

In the following web document there is an array called fruits with four elements, join() method is used in different ways : using the default separator, then a comma with a space separator, and then a hyphen separator.

HTML Code

<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="utf8" />
<title>JavaScript join() method Example-1</title>
<style type="text/css">
h1 {color:red}
</style>
</head>
<body>
<h1>JavaScript : join() method</h1>
<script src="array-join-example1.js">
</script>
</body>
</html>

JS Code

var fruits = new Array("Orange", "Apple", "Banana", "Chery");
var fruitslist1=fruits.join();
var newParagraph = document.createElement("p");
var newText = document.createTextNode("Fruits List : " + fruitslist1 ); 
newParagraph.appendChild(newText);
document.body.appendChild(newParagraph);

var fruitslist2=fruits.join(', ');
var newParagraph1 = document.createElement("p");
var newText1 = document.createTextNode("Fruits List : " + fruitslist2); 
newParagraph1.appendChild(newText1); 
document.body.appendChild(newParagraph1); 

var fruitslist3=fruits.join('-');
var newParagraph2 = document.createElement("p");
var newText2 = document.createTextNode("Fruits List : " + fruitslist3);
newParagraph2.appendChild(newText2);
document.body.appendChild(newParagraph2);

View the example in the browser

Practice the example online

JavaScript join() method Example-1

See also :

JavaScript Core objects, methods, properties.

Previous: JavaScript concat() Method : Array Object
Next: JavaScript pop() Method: Array Object

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JavaScript: Tips of the Day

Returns true if the elements of the first array are contained in the second one regardless of order, false otherwise

Example:

const tips_ContainedIn = (a, b) => {
  for (const v of new Set(a)) {
    if (!b.some(e => e === v) || a.filter(e => e === v).length > b.filter(e => e === v).length)
      return false;
  }
  return true;
};

console.log(tips_ContainedIn([1, 4, 5], [2, 4, 1, 5, 6]));

Output:

true