PHP Exercises: Check a given array of integers and return true if there is a 3 with a 5 somewhere later in the given array

Last update on April 16 2025 12:51:54 (UTC/GMT +8 hours)

118. Array Contains 3 Followed Later by 5

Write a PHP program to check a given array of integers and return true if there is a 3 with a 5 somewhere later in the given array.

Sample Solution:

PHP Code :

<?php
// Define a function named 'test' that takes an array of numbers as a parameter
function test($numbers)
 { 
    // Initialize a variable $three with a value of false
    $three = false;

    // Iterate through the elements of the array using a for loop
    for ($i = 0; $i < sizeof($numbers); $i++)
    {
        // Check if both $three is true and the current element is equal to 5, return true if true
        if ($three && $numbers[$i] == 5) return true;
        
        // Check if the current element is equal to 3, set $three to true if true
        if ($numbers[$i] == 3) $three = true;
    }

    // Return false if there are no occurrences of 3 followed by 5 in the array
    return false;
 }   

// Use 'var_dump' to print the result of calling 'test' with different arrays
var_dump(test([3, 5, 1, 3, 7]));
var_dump(test([1, 2, 3, 4]));
var_dump(test([3, 3, 5, 5, 5, 5]));
var_dump(test([2, 5, 5, 7, 8, 10]));
?>

Sample Output:

bool(true)
bool(false)
bool(true)
bool(false)

Flowchart:

For more Practice: Solve these Related Problems:

• Write a PHP script to scan an array and return true if a 3 appears before a 5, regardless of the gap between them.
• Write a PHP function to check if the first occurrence of 3 in an array is followed at any later point by a 5.
• Write a PHP program to iterate over an array and use flags to indicate whether a 3 is encountered before any subsequent 5.
• Write a PHP script to implement logic that sets a marker upon encountering a 3 and then verifies if a 5 appears later in the array.

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