PHP Exercises: Check a given array of integers and return true if the given array contains either 2 even or 2 odd values all next to each other

PHP Basic Algorithm: Exercise-119 with Solution

Write a PHP program to check a given array of integers and return true if the given array contains either 2 even or 2 odd values all next to each other.

Sample Solution:

PHP Code :

<?php
// Define a function named 'test' that takes an array of numbers as a parameter
function test($numbers)
 { 
    // Initialize variables $tot_odd and $tot_even with values of 0
    $tot_odd = 0;
    $tot_even = 0;

    // Iterate through the elements of the array using a for loop
    for ($i = 0; $i < sizeof($numbers); $i++)
    {
        // Check if both $tot_odd and $tot_even are less than 2
        if ($tot_odd < 2 && $tot_even < 2)
        {
            // Check if the current element is even
            if ($numbers[$i] % 2 == 0)
            {
                // Increment $tot_even and reset $tot_odd if the element is even
                $tot_even++;
                $tot_odd = 0;
            }
            else
            {
                // Increment $tot_odd and reset $tot_even if the element is odd
                $tot_odd++;
                $tot_even = 0;
            }
        }
    }

    // Return true if there are two consecutive even or odd numbers, otherwise false
    return $tot_odd == 2 || $tot_even == 2;
 }   

// Use 'var_dump' to print the result of calling 'test' with different arrays
var_dump(test([3, 5, 1, 3, 7]));
var_dump(test([1, 2, 3, 4]));
var_dump(test([3, 3, 5, 5, 5, 5]));
var_dump(test([2, 4, 5, 6]));
?>

Sample Output:

bool(true)
bool(false)
bool(true)
bool(true)

Flowchart:

PHP Code Editor:

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