PHP Exercises: Check which number nearest to the value 100 among two given integers

PHP Basic Algorithm: Exercise-19 with Solution

Write a PHP program to check which number nearest to the value 100 among two given integers. Return 0 if the two numbers are equal.

Sample Solution:

PHP Code :

<?php
// Define a function that takes two parameters and returns the one closer to the value 100
function test($x, $y) 
{
   // Define the target value
   $n = 100;
   
   // Calculate the absolute difference between $x and $n
   $val = abs($x - $n);
   
   // Calculate the absolute difference between $y and $n
   $val2 = abs($y - $n);
   
   // Compare the absolute differences and return the value closer to $n
   return $val == $val2 ? 0 : ($val < $val2 ? $x : $y);
}

// Test the function with different sets of values
echo test(78, 95)."\n";
echo test(95, 95)."\n";
echo test(99, 70)."\n";
?>

Explanation:

• Function Definition:
• The test function takes two parameters, $x and $y.
• Target Value:
• A variable $n is defined and set to 100, representing the target value to compare against.
• Absolute Differences:
• The absolute difference between $x and $n is calculated and stored in $val.
• The absolute difference between $y and $n is calculated and stored in $val2.
• Comparison and Return:
• If $val (difference of $x from 100) equals $val2 (difference of $y from 100), the function returns 0 (indicating both are equally close).
• If $val is smaller than $val2, the function returns $x (as it’s closer to 100).
• Otherwise, it returns $y (indicating $y is closer to 100).

Output:

95
0
99

Pictorial Presentation:

Flowchart:

PHP Code Editor:

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