PHP Exercises: Get the absolute difference between n and 51

PHP Basic Algorithm: Exercise-2 with Solution

Write a PHP program to get the absolute difference between n and 51. If n is greater than 51 return triple the absolute difference.

Sample Solution:

PHP Code :

<?php
// Define a function named "test" that takes a parameter $n
function test($n) 
{
    // Declare a variable $x and assign it the value 51
    $x = 51;

    // Check if $n is greater than $x
    if ($n > $x)
    {
        // If true, return the result of multiplying the difference between $n and $x by 3
        return ($n - $x) * 3;
    }

    // If false, return the difference between $x and $n
    return $x - $n;
}

// Call the test function with argument 53 and echo the result
echo test(53) . "\n";

// Call the test function with argument 30 and echo the result
echo test(30) . "\n";

// Call the test function with argument 51 and echo the result
echo test(51) . "\n";
?>

Explanation:

• Function Definition:
• A function named test is defined with a single parameter $n.
• Variable Initialization:
• Inside the function, a variable $x is declared and set to the value 51.
• Conditional Check:
• The function checks if $n is greater than $x (51).
• If $n is greater than $x: It returns ( $n - $x ) * 3, which is three times the difference between $n and $x.
• If $n is not greater than $x: It returns $x - $n, the difference between $x and $n.
• Function Calls and Output:
• First Call: echo test(53);
• Since 53 is greater than 51, it outputs (53 - 51) * 3 = 6.
• Second Call: echo test(30);
• Since 30 is less than 51, it outputs 51 - 30 = 21.
• Third Call: echo test(51);
• Since 51 is equal to 51, it outputs 51 - 51 = 0

Output:

6
21
0

Visual Presentation:

Flowchart:

PHP Code Editor:

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