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Python BeautifulSoup: Wrap an element in the specified tag and create the new wrapper

BeautifulSoup: Exercise-35 with Solution

Write a Python program to wrap an element in the specified tag and create the new wrapper.

Sample Solution:

Python Code:

from bs4 import BeautifulSoup
soup = BeautifulSoup("<p>Python exercises.</p>", "lxml")
print("Original Markup:")
print(soup.p.string.wrap(soup.new_tag("i")))
print("\nNew Markup:")
print(soup.p.wrap(soup.new_tag("div")))

Sample Output:

Original Markup:
<i>Python exercises.</i>

New Markup:
<div><p><i>Python exercises.</i></p></div>

Python Code Editor:

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Previous: Write a Python program to remove a tag or string from a given tree of html document and replace it with the given tag or string.
Next: Write a Python program to replace a given tag with whatever’s inside a given tag.

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Python: Tips of the Day

Getting the last element of a list:

some_list[-1] is the shortest and most Pythonic.

In fact, you can do much more with this syntax. The some_list[-n] syntax gets the nth-to-last element. So some_list[-1] gets the last element, some_list[-2] gets the second to last, etc, all the way down to some_list[-len(some_list)], which gives you the first element.

You can also set list elements in this way. For instance:

>>> some_list = [1, 2, 3]
>>> some_list[-1] = 5 # Set the last element
>>> some_list[-2] = 3 # Set the second to last element
>>> some_list
[1, 3, 5]

Note that getting a list item by index will raise an IndexError if the expected item doesn't exist. This means that some_list[-1] will raise an exception if some_list is empty, because an empty list can't have a last element.

Ref: https://bit.ly/3d8TfFP