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Python: Check if a given string contains two similar consecutive letters

Python Basic - 1: Exercise-124 with Solution

Write a Python program to check if a given string contains two similar consecutive letters.

Sample Solution-1:

Python Code:

def test(str1):
    return any(c1 == c2 for c1, c2 in zip(str1, str1[1:]))
str = "PHP"
print("Original string: ",str)
print("Check for consecutive similar letters! ",test(str))
str = "PHHP"
print("\nOriginal string: ",str)
print("Check for consecutive similar letters! ",test(str))
str = "PHPP"
print("\nOriginal string: ",str)
print("Check for consecutive similar letters! ",test(str))

Sample Output:

Original string:  PHP
Check for consecutive similar letters!  False

Original string:  PHHP
Check for consecutive similar letters!  True

Original string:  PHPP
Check for consecutive similar letters!  True

Flowchart:

Flowchart: Python - Check if a given string contains two similar consecutive letters.

Sample Solution-2:

Python Code:

def test(str1):
    for el in str1:
        if el*2 in str1:
            return True
    return False

str = "PHP"
print("Original string: ",str)
print("Check for consecutive similar letters! ",test(str))
str = "PHHP"
print("\nOriginal string: ",str)
print("Check for consecutive similar letters! ",test(str))
str = "PHPP"
print("\nOriginal string: ",str)
print("Check for consecutive similar letters! ",test(str))

Sample Output:

Original string:  PHP
Check for consecutive similar letters!  False

Original string:  PHHP
Check for consecutive similar letters!  True

Original string:  PHPP
Check for consecutive similar letters!  True

Flowchart:

Flowchart: Python - Check if a given string contains two similar consecutive letters.

Python Code Editor:

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Next: Write a Python program to reverse a given string in lower case.

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Python: Tips of the Day

How to make a flat list out of list of lists?

Given a list of lists l

flat_list = [item for sublist in l for item in sublist]

which means:

flat_list = []
for sublist in l:
    for item in sublist:
        flat_list.append(item)

is faster than the shortcuts posted so far. (l is the list to flatten.) Here is the corresponding function:

flatten = lambda l: [item for sublist in l for item in sublist]

As evidence, you can use the timeit module in the standard library:

$ python -mtimeit -s'l=[[1,2,3],[4,5,6], [7], [8,9]]*99' '[item for sublist in l for item in sublist]'
10000 loops, best of 3: 143 usec per loop
$ python -mtimeit -s'l=[[1,2,3],[4,5,6], [7], [8,9]]*99' 'sum(l, [])'
1000 loops, best of 3: 969 usec per loop
$ python -mtimeit -s'l=[[1,2,3],[4,5,6], [7], [8,9]]*99' 'reduce(lambda x,y: x+y,l)'
1000 loops, best of 3: 1.1 msec per loop

Explanation: the shortcuts based on + (including the implied use in sum) are, of necessity, O(L**2) when there are L sublists -- as the intermediate result list keeps getting longer, at each step a new intermediate result list object gets allocated, and all the items in the previous intermediate result must be copied over (as well as a few new ones added at the end). So, for simplicity and without actual loss of generality, say you have L sublists of I items each: the first I items are copied back and forth L-1 times, the second I items L-2 times, and so on; total number of copies is I times the sum of x for x from 1 to L excluded, i.e., I * (L**2)/2.

The list comprehension just generates one list, once, and copies each item over (from its original place of residence to the result list) also exactly once.

Ref: https://bit.ly/3dKsNTR