w3resource

Python: Largest and smallest digit of a given number

Python Basic - 1: Exercise-145 with Solution

Write a Python program to find the largest and smallest digit of a given number.

Sample Solution:

Python Code:

def Largest_Smallest_digit(n):
   largest_digit = 0
   smallest_digit = 9
   while (n):
       digit = n % 10
       # largest digit
       largest_digit = max(digit, largest_digit)
       # smallest digit
       smallest_digit = min(digit, smallest_digit)
       n = n // 10
   return largest_digit, smallest_digit
n = 9387422
print("Original Number:", n)
result = Largest_Smallest_digit(n)
print("Largest Digit of the said number:", result[0])
print("Smallest Digit of the said number:", result[1])
n = 500
print("\nOriginal Number:", n)
result = Largest_Smallest_digit(n)
print("Largest Digit of the said number:", result[0])
print("Smallest Digit of the said number:", result[1])
n = 231548
print("\nOriginal Number:", n)
result = Largest_Smallest_digit(n)
print("Largest Digit of the said number:", result[0])
print("Smallest Digit of the said number:", result[1])

Sample Output:

Original Number: 9387422
Largest Digit of the said number: 9
Smallest Digit of the said number: 2

Original Number: 500
Largest Digit of the said number: 5
Smallest Digit of the said number: 0

Original Number: 231548
Largest Digit of the said number: 8
Smallest Digit of the said number: 1

Flowchart:

Flowchart: Python - Largest and smallest digit of a given number.

Visualize Python code execution:

The following tool visualize what the computer is doing step-by-step as it executes the said program:


Python Code Editor:

Have another way to solve this solution? Contribute your code (and comments) through Disqus.

Previous: Write a Python program to convert integer to string.
Next: Python String Exercise Home.

What is the difficulty level of this exercise?

Test your Programming skills with w3resource's quiz.



Python: Tips of the Day

Iterating over dictionaries using 'for' loops:

I am a bit puzzled by the following code: d = {'x': 1, 'y': 2, 'z': 3} for key in d: print key, 'corresponds to', d[key] What I don't understand is the key portion. How does Python recognize ...

key is just a variable name.

for key in d:

For Python 3.x:

for key, value in d.items():

For Python 2.x:

for key, value in d.iteritems():

To test for yourself, change the word key to poop.

In Python 3.x, iteritems() was replaced with simply items(), which returns a set-like view backed by the dict, like iteritems() but even better. This is also available in 2.7 as viewitems().

The operation items() will work for both 2 and 3, but in 2 it will return a list of the dictionary's (key, value) pairs, which will not reflect changes to the dict that happen after the items() call. If you want the 2.x behavior in 3.x, you can call list(d.items()).

Ref: https://bit.ly/37dm0Qo