# Python Exercises: Check square root and cube root of a number

## Python Basic - 1: Exercise-146 with Solution

A Python list contains two positive integers. Write a Python program to check whether the cube root of the first number is equal to the square root of the second number.

**Sample Data:**

([8, 4]) -> True

([64, 16]) -> True

([64, 36]) -> False

**Sample Solution-1:**

**Python Code:**

```
# Function to check if the square root of the first number is equal to the cube root of the second number.
def test(nums):
# Extract the two numbers from the list.
x = nums[0]
y = nums[1]
# Calculate the square root of y.
t = y**0.5
# Check if the square of the square root is equal to the cube of the first number.
if(x == t*t*t):
return True
else:
return False
# Example usage of the function with different lists of positive numbers.
nums = [8, 4]
print("Original list of positive numbers:")
print(nums)
print("Check square root and cube root of the said numbers:")
print(test(nums))
nums = [64, 16]
print("\nOriginal list of positive numbers:")
print(nums)
print("Check square root and cube root of the said numbers:")
print(test(nums))
nums = [64, 36]
print("\nOriginal list of positive numbers:")
print(nums)
print("Check square root and cube root of the said numbers:")
print(test(nums))
```

Sample Output:

Original list of positive numbers: [8, 4] True Check square root and cube root of the said numbers: Original list of positive numbers: [64, 16] Check square root and cube root of the said numbers: True Original list of positive numbers: [64, 36] Check square root and cube root of the said numbers: False

**Explanation:**

Here is a breakdown of the above Python code:

- Function definition:
- def test(nums):: Defines a function named "test()" that takes a list of two numbers (nums) as input.
- Variable assignment:
- x = nums[0]: Assigns the first element of the list to variable 'x'.
- y = nums[1]: Assigns the second element of the list to variable 'y'.
- Square root calculation:
- t = y**0.5: Calculates the square root of 'y' and assigns it to the variable 't'.
- Conditional check:
- if(x == t*t*t):: Checks if the cube of the square root (t) is equal to the cube of x.
- Return Statement:
- return True or return False: Returns 'True' if the condition is satisfied, otherwise 'False'.

**Flowchart:**

**Sample Solution-2:**

**Python Code:**

```
# Function to check if the cube root of the square root of the second number is equal to the first number.
def test(nums):
# Check if the cube root of the square root of the second number is equal to the first number.
return (((nums[1] ** 0.5) ** 3) == nums[0])
# Example usage of the function with different lists of positive numbers.
nums = [8, 4]
print("Original list of positive numbers:")
print(nums)
print("Check square root and cube root of the said numbers:")
print(test(nums))
nums = [64, 16]
print("\nOriginal list of positive numbers:")
print(nums)
print("Check square root and cube root of the said numbers:")
print(test(nums))
nums = [64, 36]
print("\nOriginal list of positive numbers:")
print(nums)
print("Check square root and cube root of the said numbers:")
print(test(nums))
```

Sample Output:

Original list of positive numbers: [8, 4] True Check square root and cube root of the said numbers: Original list of positive numbers: [64, 16] Check square root and cube root of the said numbers: True Original list of positive numbers: [64, 36] Check square root and cube root of the said numbers: False

**Explanation:**

Here is a breakdown of the above Python code:

- Function definition:
- def test(nums):: Defines a function named "test()" that takes a list of two numbers (nums) as input.
- Conditional check:
- return (((nums[1] 0.5) 3) == nums[0]): Checks if the cube root of the square root of the second number is equal to the first number.
- Example usage:
- Demonstrates the usage of the function with different lists of positive numbers and prints the results.

**Flowchart:**

**Python Code Editor:**

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