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Python: Accepts six numbers as input and sorts them in descending order

Python Basic - 1: Exercise-42 with Solution

Write a Python program that accepts six numbers as input and sorts them in descending order.

Input:
Input consists of six numbers n1, n2, n3, n4, n5, n6 (-100000 ≤ n1, n2, n3, n4, n5, n6 ≤ 100000). The six numbers are separated by a space.
Input six integers:
15 30 25 14 35 40
After sorting the said integers:
40 35 30 25 15 14

Pictorial Presentation:

Python: Accepts six numbers as input and sorts them in descending order

Sample Solution:

Python Code:

print("Input six integers:")
nums = list(map(int, input().split()))
nums.sort()
nums.reverse()
print("After sorting the said ntegers:")
print(*nums)

Sample Output:

Input six integers:
 15 30 25 14 35 40
After sorting the said ntegers:
40 35 30 25 15 14

Flowchart:

Flowchart: Python - Accepts six numbers as input and sorts them in descending order

Python Code Editor:

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Previous: Write a Python program to compute and print sum of two given integers (more than or equal to zero). If given integers or the sum have more than 80 digits, print "overflow".
Next: Write a Python program to test whether two lines PQ and RS are parallel. The four points are P(x1, y1), Q(x2, y2), R(x3, y3), S(x4, y4).

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Python: Tips of the Day

Iterating over dictionaries using 'for' loops:

I am a bit puzzled by the following code: d = {'x': 1, 'y': 2, 'z': 3} for key in d: print key, 'corresponds to', d[key] What I don't understand is the key portion. How does Python recognize ...

key is just a variable name.

for key in d:

For Python 3.x:

for key, value in d.items():

For Python 2.x:

for key, value in d.iteritems():

To test for yourself, change the word key to poop.

In Python 3.x, iteritems() was replaced with simply items(), which returns a set-like view backed by the dict, like iteritems() but even better. This is also available in 2.7 as viewitems().

The operation items() will work for both 2 and 3, but in 2 it will return a list of the dictionary's (key, value) pairs, which will not reflect changes to the dict that happen after the items() call. If you want the 2.x behavior in 3.x, you can call list(d.items()).

Ref: https://bit.ly/37dm0Qo