Python: Compute and print sum of two given integers

Last update on April 17 2025 13:05:49 (UTC/GMT +8 hours)

Sum with Overflow Check

Write a Python program to compute and print the sum of two given integers (greater or equal to zero). In the event that the given integers or the sum exceed 80 digits, print "overflow".

Sample Solution:

Python Code:

# Print statement to prompt the user to input the first integer
print("Input first integer:")

# Take user input and convert it to an integer
x = int(input())

# Print statement to prompt the user to input the second integer
print("Input second integer:")

# Take user input and convert it to an integer
y = int(input())

# Check if any of the integers or their sum exceeds 10^80
if x >= 10 ** 80 or y >= 10 ** 80 or x + y >= 10 ** 80:
    print("Overflow!")  # Print overflow message if the condition is met
else:
    print("Sum of the two integers: ", x + y)  # Print the sum if no overflow occurs

Sample Output:

Input first integer:
 25
Input second integer:
 22
Sum of the two integers:  47

Explanation:

The above Python program prompts the user to input two integers, 'x' and 'y'. It then checks whether any of these integers or their sum exceeds the value of 10^80. If the condition is met, indicating that the result is too large to be represented, it prints "Overflow!". Otherwise, it calculates and prints the sum of the two integers. The purpose is to prevent integer overflow for extremely large values.

Flowchart:

For more Practice: Solve these Related Problems:

Write a Python program to compute the product of two integers and output "overflow" if the result exceeds 80 digits.
Write a Python program to calculate the factorial of a number and print "overflow" if the result contains more than 80 digits.
Write a Python program to subtract two large integers and check for overflow conditions when the result exceeds 80 digits.
Write a Python program to compute exponentiation of two integers and output "overflow" if the result is larger than 80 digits.

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Python Code Editor:

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