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Python: Find the middle character(s) of a given string

Python Basic - 1: Exercise-93 with Solution

Write a Python program to find the middle character(s) of a given string. If the length of the string is even return the two middle characters. If the length of the string is odd, return the middle character.

Sample Solution:

Python Code:

def middle_char(txt):
  return txt[(len(txt)-1)//2:(len(txt)+2)//2]
text = "Python"
print("Original string: ",text)
print("Middle character(s) of the said string: ",middle_char(text))
text = "PHP"
print("Original string: ",text)
print("Middle character(s) of the said string: ",middle_char(text))
text = "Java"
print("Original string: ",text)
print("Middle character(s) of the said string: ",middle_char(text))

Sample Output:

Original string:  Python
Middle character(s) of the said string:  th
Original string:  PHP
Middle character(s) of the said string:  H
Original string:  Java
Middle character(s) of the said string:  av

Pictorial Presentation:

Python: Compute cumulative sum of numbers of a given list.
Python: Compute cumulative sum of numbers of a given list.

Flowchart:

Flowchart: Python - Compute cumulative sum of numbers of a given list.

Python Code Editor:

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Next: Write a Python program to find the largest product of the pair of adjacent elements from a given list of integers.

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Python: Tips of the Day

Iterating over dictionaries using 'for' loops:

I am a bit puzzled by the following code: d = {'x': 1, 'y': 2, 'z': 3} for key in d: print key, 'corresponds to', d[key] What I don't understand is the key portion. How does Python recognize ...

key is just a variable name.

for key in d:

For Python 3.x:

for key, value in d.items():

For Python 2.x:

for key, value in d.iteritems():

To test for yourself, change the word key to poop.

In Python 3.x, iteritems() was replaced with simply items(), which returns a set-like view backed by the dict, like iteritems() but even better. This is also available in 2.7 as viewitems().

The operation items() will work for both 2 and 3, but in 2 it will return a list of the dictionary's (key, value) pairs, which will not reflect changes to the dict that happen after the items() call. If you want the 2.x behavior in 3.x, you can call list(d.items()).

Ref: https://bit.ly/37dm0Qo