Python: Check every even index contains an even number and odd index contains odd number of a given list

Python Basic - 1: Exercise-95 with Solution

Write a Python program that checks whether every even index contains an even number and every odd index contains an odd number of a given list.

Sample Solution:

Python Code:

def odd_even_position(nums):
           return all(nums[i]%2==i%2 for i in range(len(nums)))
nums = [2, 1, 4, 3, 6, 7, 6, 3]
print("Original list of numbers:", nums)
print("Check whether every even index contains an even number and every \nodd index contains odd number of a given list:")
print(odd_even_position(nums))
nums = [2, 1, 4, 3, 6, 7, 6, 4]
print("\nOriginal list of numbers:", nums)
print("Check whether every even index contains an even number and every \nodd index contains odd number of a given list:")
print(odd_even_position(nums))
print("\nOriginal list of numbers:", nums)
nums = [4, 1, 2]
print("Check whether every even index contains an even number and every \nodd index contains odd number of a given list:")
print(odd_even_position(nums))

Sample Output:

Original list of numbers: [2, 1, 4, 3, 6, 7, 6, 3]
Check whether every even index contains an even number and every 
odd index contains odd number of a given list:
True

Original list of numbers: [2, 1, 4, 3, 6, 7, 6, 4]
Check whether every even index contains an even number and every 
odd index contains odd number of a given list:
False

Original list of numbers: [2, 1, 4, 3, 6, 7, 6, 4]
Check whether every even index contains an even number and every 
odd index contains odd number of a given list:
True

Pictorial Presentation:

Flowchart:

Python Code Editor:

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