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Python Bisect: Find the index position of the last occurrence of a given number in a sorted list using Binary Search

Python Bisect: Exercise-6 with Solution

Write a Python program to find the index position of the last occurrence of a given number in a sorted list using Binary Search (bisect).

Sample Solution:

Python Code:

from bisect import bisect_right   
def BinarySearch(a, x): 
    i = bisect_right(a, x) 
    if i != len(a)+1 and a[i-1] == x: 
        return (i-1) 
    else: 
        return -1 
nums = [1, 2, 3, 4, 8, 8, 10, 12] 
x = 8
num_position   = BinarySearch(nums, x) 
if num_position == -1: 
    print("not presetn!") 
else: 
    print("Last occurrence of", x, "is present at", num_position)

Sample Output:

Last occurrence of 8 is present at 5

Flowchart:

Flowchart: Find the index position of the last occurrence of a given number in a sorted list using Binary Search.

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Previous: Write a Python program to find the index position of the largest value smaller than a given number in a sorted list using Binary Search (bisect).

Next: Write a Python program to find three integers which gives the sum of zero in a given array of integers using Binary Search (bisect).

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Python: Tips of the Day

How to make a chain of function decorators?

from functools import wraps

def makebold(fn):
    @wraps(fn)
    def wrapped(*args, **kwargs):
        return "<b>" + fn(*args, **kwargs) + "</b>"
    return wrapped

def makeitalic(fn):
    @wraps(fn)
    def wrapped(*args, **kwargs):
        return "<i>" + fn(*args, **kwargs) + "</i>"
    return wrapped

@makebold
@makeitalic
def hello():
    return "hello world"

@makebold
@makeitalic
def log(s):
    return s

print hello()        # returns "<b><i>hello world</i></b>"
print hello.__name__ # with functools.wraps() this returns "hello"
print log('hello')   # returns "<b><i>hello</i></b>"

Ref: https://bit.ly/3cVz5iw