# Python Bisect: Find three integers which gives the sum of zero in a given array of integers using Binary Search

## Python Bisect: Exercise-7 with Solution

Write a Python program to find three integers which give the sum of zero in a given array of integers using Binary Search (bisect).

**Sample Solution**:

**Python Code:**

```
from bisect import bisect, bisect_left
from collections import Counter
class Solution:
def three_Sum(self, nums):
"""
:type nums: List[int]
:rtype: List[List[int]]
"""
triplets = []
if len(nums) < 3:
return triplets
num_freq = Counter(nums)
nums = sorted(num_freq) # Sorted unique numbers
max_num = nums[-1]
for i, v in enumerate(nums):
if num_freq[v] >= 2:
complement = -2 * v
if complement in num_freq:
if complement != v or num_freq[v] >= 3:
triplets.append([v] * 2 + [complement])
# When all 3 numbers are different.
if v < 0: # Only when v is the smallest
two_sum = -v
# Lower/upper bound of the smaller of remainingtwo.
lb = bisect_left(nums, two_sum - max_num, i + 1)
ub = bisect(nums, two_sum // 2, lb)
for u in nums[lb : ub]:
complement = two_sum - u
if complement in num_freq and u != complement:
triplets.append([v, u, complement])
return triplets
nums = [-20, 0, 20, 40, -20, -40, 80]
s = Solution()
result = s.three_Sum(nums)
print(result)
nums = [1, 2, 3, 4, 5, -6]
result = s.three_Sum(nums)
print(result)
```

Sample Output:

[[-40, 0, 40], [-20, -20, 40], [-20, 0, 20]] [[-6, 1, 5], [-6, 2, 4]]

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**Next:**Write a Python program to find a triplet in an array such that the sum is closest to a given number. Return the sum of the three integers.

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