Python: Find the three elements that sum to zero from a set of n real numbers
Python Class: Exercise-6 with Solution
Write a Python class to find the three elements that sum to zero from a set (array) of n real numbers.
Sample Solution:
Python Code:
class py_solution:
def threeSum(self, nums):
nums, result, i = sorted(nums), [], 0
while i < len(nums) - 2:
j, k = i + 1, len(nums) - 1
while j < k:
if nums[i] + nums[j] + nums[k] < 0:
j += 1
elif nums[i] + nums[j] + nums[k] > 0:
k -= 1
else:
result.append([nums[i], nums[j], nums[k]])
j, k = j + 1, k - 1
while j < k and nums[j] == nums[j - 1]:
j += 1
while j < k and nums[k] == nums[k + 1]:
k -= 1
i += 1
while i < len(nums) - 2 and nums[i] == nums[i - 1]:
i += 1
return result
print(py_solution().threeSum([-25, -10, -7, -3, 2, 4, 8, 10]))
Sample Output:
[[-10, 2, 8], [-7, -3, 10]]
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Previous: Write a Python class to find a pair of elements (indices of the two numbers) from a given array whose sum equals a specific target number.
Next: Write a Python class to implement pow(x, n).
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Python: Tips of the Day
The Zip() Function:
>>> students = ('John', 'Mary', 'Mike') >>> ages = (15, 17, 16) >>> scores = (90, 88, 82, 17, 14) >>> for student, age, score in zip(students, ages, scores): ... print(f'{student}, age: {age}, score: {score}') ... John, age: 15, score: 90 Mary, age: 17, score: 88 Mike, age: 16, score: 82 >>> zipped = zip(students, ages, scores) >>> a, b, c = zip(*zipped) >>> print(b) (15, 17, 16)
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