Python: Sort the dictionary during the creation and print the members of the dictionary in reverse order

Python Collections: Exercise-34 with Solution

Write a Python program to create an instance of an OrderedDict using a given dictionary. Sort the dictionary during the creation and print the members of the dictionary in reverse order.

Sample Solution:

Python Code:

# Import the OrderedDict class from the collections module
from collections import OrderedDict

# Create a dictionary 'dict' with country names as keys and their international dialing codes as values
dict = {'Afghanistan': 93, 'Albania': 355, 'Algeria': 213, 'Andorra': 376, 'Angola': 244}

# Create a new OrderedDict 'new_dict' using the items of the original dictionary
new_dict = OrderedDict(dict.items())

# Loop through the keys in 'new_dict' and print each key and its corresponding value
for key in new_dict:
    print(key, new_dict[key])

# Print a message to indicate the display of keys and values in reverse order
print("\nIn reverse order:")

# Loop through the keys in 'new_dict' in reverse order and print each key and its corresponding value
for key in reversed(new_dict):
    print(key, new_dict[key]) 

Sample Output:

Afghanistan 93
Albania 355
Algeria 213
Andorra 376
Angola 244

In reverse order:
Angola 244
Andorra 376
Algeria 213
Albania 355
Afghanistan 93

Flowchart:

Python Code Editor:

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