Python: Print structure time in local time

Python Datetime: Exercise-61 with Solution

Write a Python program that takes a given number of seconds and passes since the epoch as an argument. Print structure time in local time.

Sample Solution:

Python Code:

import time
result = time.localtime(414538698)
print("\nResult:", result)
print("\nYear:", result.tm_year)

Sample Output:

Result: time.struct_time(tm_year=1983, tm_mon=2, tm_mday=19, tm_hour=21, tm_min=38, tm_sec=18, tm_wday=5, tm_yday=50, tm_isdst=0)

Year: 1983

Flowchart:

Python Code Editor:

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