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Python: Parse a string representing time and returns the structure time

Python Datetime: Exercise-63 with Solution

Write a Python program to parse a string representing time and returns the structure time.

Sample Solution:

Python Code:

import time
time_string = "22 January, 2020"
print("String representing time:",time_string)
result = time.strptime(time_string, "%d %B, %Y")
print(result)
time_string = "30 Nov 00"
print("\nString representing time:",time_string)
result = time.strptime(time_string, "%d %b %y")
print(result)
time_string = '04/11/15 11:55:23'
print("\nString representing time:",time_string)
result = time.strptime(time_string, "%m/%d/%y %H:%M:%S")
print(result)
time_string = '12-11-2019'
print("\nString representing time:",time_string)
result = time.strptime(time_string, "%m-%d-%Y")
print(result)
time_string = '13::55::26'
print("\nString representing time:",time_string)
result = time.strptime(time_string, "%H::%M::%S")
print(result)

Sample Output:

String representing time: 22 January, 2020
time.struct_time(tm_year=2020, tm_mon=1, tm_mday=22, tm_hour=0, tm_min=0, tm_sec=0, tm_wday=2, tm_yday=22, tm_isdst=-1)

String representing time: 30 Nov 00
time.struct_time(tm_year=2000, tm_mon=11, tm_mday=30, tm_hour=0, tm_min=0, tm_sec=0, tm_wday=3, tm_yday=335, tm_isdst=-1)

String representing time: 04/11/15 11:55:23
time.struct_time(tm_year=2015, tm_mon=4, tm_mday=11, tm_hour=11, tm_min=55, tm_sec=23, tm_wday=5, tm_yday=101, tm_isdst=-1)

String representing time: 12-11-2019
time.struct_time(tm_year=2019, tm_mon=12, tm_mday=11, tm_hour=0, tm_min=0, tm_sec=0, tm_wday=2, tm_yday=345, tm_isdst=-1)

String representing time: 13::55::26
time.struct_time(tm_year=1900, tm_mon=1, tm_mday=1, tm_hour=13, tm_min=55, tm_sec=26, tm_wday=0, tm_yday=1, tm_isdst=-1)

Flowchart:

Flowchart: A tuple containing 9 elements corresponding to structure time as an argument and returns a string representing it.

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