﻿ Python: Create non-repeated combinations of Cartesian product of three list - w3resource

# Python: Create non-repeated combinations of Cartesian product of three list

## Python Itertools: Exercise-30 with Solution

Write a Python program to create non-repeated combinations of the Cartesian product of a given list of four numbers.

Sample Solution:

Python Code:

``````import itertools as it
mums1 = [1, 2, 3, 4]
mums2 = [5, 6, 7, 8]
mums3 = [9, 10, 11, 12]
mums4 = [13, 14, 15, 16]
print("Original lists:")
print(mums1)
print(mums2)
print(mums3)
print(mums4)
print("\nSum of the specified range:")
for i in it.product([tuple(mums1)], it.permutations(mums2), it.permutations(mums3), it.permutations(mums4)):
print(i)
```
```

Sample Output:

```Original lists:
[1, 2, 3, 4]
[5, 6, 7, 8]
[9, 10, 11, 12]
[13, 14, 15, 16]

Sum of the specified range:
((1, 2, 3, 4), (5, 6, 7, 8), (9, 10, 11, 12), (13, 14, 15, 16))
((1, 2, 3, 4), (5, 6, 7, 8), (9, 10, 11, 12), (13, 14, 16, 15))

```

Python Code Editor:

Have another way to solve this solution? Contribute your code (and comments) through Disqus.

What is the difficulty level of this exercise?

Test your Programming skills with w3resource's quiz.

﻿

## Python: Tips of the Day

Inverts a dictionary with non-unique hashable values:

Example:

```def tips_collect_dictionary(obj):
inv_obj = {}
for key, value in obj.items():
inv_obj.setdefault(value, list()).append(key)
return inv_obj
ages = {
"Owen": 25,
"Jhon": 25,
"Pepe": 15,
}
print(tips_collect_dictionary(ages))
```

Output:

```{25: ['Owen', 'Jhon'], 15: ['Pepe']}
```

We are closing our Disqus commenting system for some maintenanace issues. You may write to us at reach[at]yahoo[dot]com or visit us at Facebook