Python: Create non-repeated combinations of Cartesian product of three list
Python Itertools: Exercise-30 with Solution
Write a Python program to create non-repeated combinations of the Cartesian product of a given list of four numbers.
Sample Solution:
Python Code:
import itertools as it
mums1 = [1, 2, 3, 4]
mums2 = [5, 6, 7, 8]
mums3 = [9, 10, 11, 12]
mums4 = [13, 14, 15, 16]
print("Original lists:")
print(mums1)
print(mums2)
print(mums3)
print(mums4)
print("\nSum of the specified range:")
for i in it.product([tuple(mums1)], it.permutations(mums2), it.permutations(mums3), it.permutations(mums4)):
print(i)
Sample Output:
Original lists: [1, 2, 3, 4] [5, 6, 7, 8] [9, 10, 11, 12] [13, 14, 15, 16] Sum of the specified range: ((1, 2, 3, 4), (5, 6, 7, 8), (9, 10, 11, 12), (13, 14, 15, 16)) ((1, 2, 3, 4), (5, 6, 7, 8), (9, 10, 11, 12), (13, 14, 16, 15))
Python Code Editor:
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Previous: Write a Python program to interleave multiple lists of the same length. Use itertools module.
Next: Write a Python program to count the frequency of consecutive duplicate elements in a given list of numbers. Use itertools module.
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Python: Tips of the Day
Inverts a dictionary with non-unique hashable values:
Example:
def tips_collect_dictionary(obj): inv_obj = {} for key, value in obj.items(): inv_obj.setdefault(value, list()).append(key) return inv_obj ages = { "Owen": 25, "Jhon": 25, "Pepe": 15, } print(tips_collect_dictionary(ages))
Output:
{25: ['Owen', 'Jhon'], 15: ['Pepe']}
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