Python: Create group of similar items of a given list
Python Itertools: Exercise-42 with Solution
Write a Python program to create groups of similar items from a given list.
Sample Solution:
Python Code:
import itertools as it
def group_similar_items(seq):
result = [list(el) for _, el in it.groupby(seq, lambda x: x.split('_')[0])]
return result
colors = ['red_1', 'red_2', 'green_1', 'green_2', 'green_3', 'orange_1', 'orange_2']
print("Original list:")
print(colors)
print("\nGroup similar items of the said list:")
print(group_similar_items(colors))
colors = ['red_1', 'green-1', 'green_2', 'green_3', 'orange-1', 'orange_2']
print("\nOriginal list:")
print(colors)
print("\nGroup similar items of the said list:")
print(group_similar_items(colors))
Sample Output:
Original list: ['red_1', 'red_2', 'green_1', 'green_2', 'green_3', 'orange_1', 'orange_2'] Group similar items of the said list: [['red_1', 'red_2'], ['green_1', 'green_2', 'green_3'], ['orange_1', 'orange_2']] Original list: ['red_1', 'green-1', 'green_2', 'green_3', 'orange-1', 'orange_2'] Group similar items of the said list: [['red_1'], ['green-1'], ['green_2', 'green_3'], ['orange-1'], ['orange_2']]
Python Code Editor:
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Python: Tips of the Day
Inverts a dictionary with non-unique hashable values:
Example:
def tips_collect_dictionary(obj): inv_obj = {} for key, value in obj.items(): inv_obj.setdefault(value, list()).append(key) return inv_obj ages = { "Owen": 25, "Jhon": 25, "Pepe": 15, } print(tips_collect_dictionary(ages))
Output:
{25: ['Owen', 'Jhon'], 15: ['Pepe']}
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