Python: Make an iterator that drops elements from the iterable as soon as a condition is true
Python Itertools: Exercise-7 with Solution
Write a Python program to make an iterator that drops elements from the iterable as long as the elements are negative; afterwards, it returns every element.
Sample Solution:
Python Code:
import itertools as it
def drop_while(nums):
return it.takewhile(lambda x : x < 0, nums)
nums = [-1,-2,-3,4,-10,2,0,5,12]
print("Original list: ",nums)
result = drop_while(nums)
print("Drop elements from the said list as long as the elements are negative\n",list(result))
#Alternate solution
def negative_num(x):
return x < 0
def drop_while(nums):
return it.dropwhile(negative_num, nums)
nums = [-1,-2,-3,4,-10,2,0,5,12]
print("Original list: ",nums)
result = drop_while(nums)
print("Drop elements from the said list as long as the elements are negative\n",list(result))
Sample Output:
Original list: [-1, -2, -3, 4, -10, 2, 0, 5, 12] Drop elements from the said list as long as the elements are negative [-1, -2, -3] Original list: [-1, -2, -3, 4, -10, 2, 0, 5, 12] Drop elements from the said list as long as the elements are negative [4, -10, 2, 0, 5, 12]
Python Code Editor:
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Previous: Write a Python program to make an iterator that drops elements from the iterable as soon as an element is a positive number.
Next: Write a Python program to create an iterator that returns consecutive keys and groups from an iterable.
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Python: Tips of the Day
Inverts a dictionary with non-unique hashable values:
Example:
def tips_collect_dictionary(obj): inv_obj = {} for key, value in obj.items(): inv_obj.setdefault(value, list()).append(key) return inv_obj ages = { "Owen": 25, "Jhon": 25, "Pepe": 15, } print(tips_collect_dictionary(ages))
Output:
{25: ['Owen', 'Jhon'], 15: ['Pepe']}
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