Python: Make an iterator that returns consecutive keys and groups from the iterable
Python Itertools: Exercise-8 with Solution
Write a Python program to create an iterator that returns consecutive keys and groups from an iterable.
Sample Solution:
Python Code:
import itertools as it
print("Iterate over characters of a string and display\nconsecutive keys and groups from the iterable:")
str1 = 'AAAAJJJJHHHHNWWWEERRRSSSOOIIU'
data_groupby = it.groupby(str1)
for key, group in data_groupby:
print('Key:', key)
print('Group:', list(group))
print("\nIterate over elements of a list and display\nconsecutive keys and groups from the iterable:")
str1 = 'AAAAJJJJHHHHNWWWEERRRSSSOOIIU'
str1 = [1,2,2,3,4,4,5,5,5,6,6,7,7,7,8]
data_groupby = it.groupby(str1)
for key, group in data_groupby:
print('Key:', key)
print('Group:', list(group))
Sample Output:
Iterate over characters of a string and display consecutive keys and groups from the iterable: Key: A Group: ['A', 'A', 'A', 'A'] Key: J Group: ['J', 'J', 'J', 'J'] Key: H Group: ['H', 'H', 'H', 'H'] Key: N Group: ['N'] Key: W Group: ['W', 'W', 'W'] Key: E Group: ['E', 'E'] Key: R Group: ['R', 'R', 'R'] Key: S Group: ['S', 'S', 'S'] Key: O Group: ['O', 'O'] Key: I Group: ['I', 'I'] Key: U Group: ['U'] Iterate over elements of a list and display consecutive keys and groups from the iterable: Key: 1 Group: [1] Key: 2 Group: [2, 2] Key: 3 Group: [3] Key: 4 Group: [4, 4] Key: 5 Group: [5, 5, 5] Key: 6 Group: [6, 6] Key: 7 Group: [7, 7, 7] Key: 8 Group: [8]
Python Code Editor:
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