Python: Find numbers within a given range where every number is divisible by every digit it contains

Last update on April 22 2025 12:55:48 (UTC/GMT +8 hours)

24. Divisible Range Checker Lambda

Write a Python program to find numbers within a given range where every number is divisible by every digit it contains.

Sample Solution:

Python Code :

# Define a function named 'divisible_by_digits' that takes two parameters: start_num and end_num
def divisible_by_digits(start_num, end_num):
    # Return a list comprehension that generates a list of numbers within the range of start_num to end_num (inclusive)
    # The list comprehension filters numbers based on a condition specified in the 'if' statement
    return [
        n for n in range(start_num, end_num + 1)
        if not any(map(lambda x: int(x) == 0 or n % int(x) != 0, str(n)))
    ]

# Print the result of calling the 'divisible_by_digits' function with arguments 1 and 22
print(divisible_by_digits(1, 22))

Sample Output:

[1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 12, 15, 22]

For more Practice: Solve these Related Problems:

Write a Python program to find numbers within a given range that are divisible by the sum of their digits using lambda.
Write a Python program to find numbers within a given range where the number equals the product of its digits using lambda.
Write a Python program to identify numbers within a range that are divisible by each of their non-zero digits using lambda.
Write a Python program to find numbers within a range that remain divisible after sequentially removing one digit at a time using lambda.

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Next: Write a Python program to create the next bigger number by rearranging the digits of a given number.

Python Code Editor:

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