﻿ Python: Find numbers within a given range where every number is divisible by every digit it contains - w3resource

# Python: Find numbers within a given range where every number is divisible by every digit it contains

## Python Lambda: Exercise-24 with Solution

Write a Python program to find numbers within a given range where every number is divisible by every digit it contains.

Sample Solution:

Python Code :

``````def divisible_by_digits(start_num, end_num):
return [n for n in range(start_num, end_num+1) \
if not any(map(lambda x: int(x) == 0 or n%int(x) != 0, str(n)))]
print(divisible_by_digits(1,22))
``````

Sample Output:

```[1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 12, 15, 22]
```

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## Python: Tips of the Day

Python: Cache results with decorators

There is a great way to cache functions with decorators in Python. Caching will help save time and precious resources when there is an expensive function at hand.

Implementation is easy, just import lru_cache from functools library and decorate your function using @lru_cache.

```from functools import lru_cache

@lru_cache(maxsize=None)
def fibo(a):
if a <= 1:
return a
else:
return fibo(a-1) + fibo(a-2)

for i in range(20):
print(fibo(i), end="|")

print("\n\n", fibo.cache_info())
```

Output:

```0|1|1|2|3|5|8|13|21|34|55|89|144|233|377|610|987|1597|2584|4181|

CacheInfo(hits=36, misses=20, maxsize=None, currsize=20)```