# Python: Find numbers within a given range where every number is divisible by every digit it contains

## Python Lambda: Exercise-24 with Solution

Write a Python program to find numbers within a given range where every number is divisible by every digit it contains.

**Sample Solution**:

**Python Code :**

```
def divisible_by_digits(start_num, end_num):
return [n for n in range(start_num, end_num+1) \
if not any(map(lambda x: int(x) == 0 or n%int(x) != 0, str(n)))]
print(divisible_by_digits(1,22))
```

Sample Output:

[1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 12, 15, 22]

## Visualize Python code execution:

The following tool visualize what the computer is doing step-by-step as it executes the said program:

**Python Code Editor:**

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**Previous:** Write a Python program to calculate the sum of the positive and negative numbers of a given list of numbers using lambda function.

**Next:** Write a Python program to create the next bigger number by rearranging the digits of a given number.

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## Python: Tips of the Day

**Python: Cache results with decorators**

There is a great way to cache functions with decorators in Python. Caching will help save time and precious resources when there is an expensive function at hand.

Implementation is easy, just import lru_cache from functools library and decorate your function using @lru_cache.

from functools import lru_cache @lru_cache(maxsize=None) def fibo(a): if a <= 1: return a else: return fibo(a-1) + fibo(a-2) for i in range(20): print(fibo(i), end="|") print("\n\n", fibo.cache_info())

Output:

0|1|1|2|3|5|8|13|21|34|55|89|144|233|377|610|987|1597|2584|4181| CacheInfo(hits=36, misses=20, maxsize=None, currsize=20)

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