﻿ Python: Next bigger number by rearranging the digits of a given number - w3resource # Python: Next bigger number by rearranging the digits of a given number

## Python Lambda: Exercise-25 with Solution

Write a Python program to create the next bigger number by rearranging the digits of a given number.

Sample Solution:

Python Code :

``````def rearrange_bigger(n):
#Break the number into digits and store in a list
nums = list(str(n))
for i in range(len(nums)-2,-1,-1):
if nums[i] < nums[i+1]:
z = nums[i:]
y = min(filter(lambda x: x > z, z))
z.remove(y)
z.sort()
nums[i:] = [y] + z
return int("".join(nums))
return False
n = 12
print("Original number:",n)
print("Next bigger number:",rearrange_bigger(n))

n = 10
print("\nOriginal number:",n)
print("Next bigger number:",rearrange_bigger(n))

n = 201
print("\nOriginal number:",n)
print("Next bigger number:",rearrange_bigger(n))
n = 102
print("\nOriginal number:",n)
print("Next bigger number:",rearrange_bigger(n))
n = 445
print("\nOriginal number:",n)
print("Next bigger number:",rearrange_bigger(n))
``````

Sample Output:

```Original number: 12
Next bigger number: 21

Original number: 10
Next bigger number: False

Original number: 201
Next bigger number: 210

Original number: 102
Next bigger number: 120

Original number: 445
Next bigger number: 454
```

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## Python: Tips of the Day

Returns all the elements of a list except the last one

Example:

```def tips_initial(lst):
return lst[0:-1]

print(tips_initial([1, 2, 3, 4]))
```

Output:

```[1, 2, 3]
```