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Python: Next bigger number by rearranging the digits of a given number

Python Lambda: Exercise-25 with Solution

Write a Python program to create the next bigger number by rearranging the digits of a given number.

Sample Solution:

Python Code :

def rearrange_bigger(n):
    #Break the number into digits and store in a list
    nums = list(str(n))
    for i in range(len(nums)-2,-1,-1):
        if nums[i] < nums[i+1]:
            z = nums[i:]
            y = min(filter(lambda x: x > z[0], z))
            z.remove(y)
            z.sort()
            nums[i:] = [y] + z
            return int("".join(nums))
    return False
n = 12
print("Original number:",n)
print("Next bigger number:",rearrange_bigger(n))

n = 10
print("\nOriginal number:",n)
print("Next bigger number:",rearrange_bigger(n))
      
n = 201
print("\nOriginal number:",n)
print("Next bigger number:",rearrange_bigger(n))
n = 102
print("\nOriginal number:",n)
print("Next bigger number:",rearrange_bigger(n))
n = 445
print("\nOriginal number:",n)
print("Next bigger number:",rearrange_bigger(n))

Sample Output:

Original number: 12
Next bigger number: 21

Original number: 10
Next bigger number: False

Original number: 201
Next bigger number: 210

Original number: 102
Next bigger number: 120

Original number: 445
Next bigger number: 454

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Previous: Write a Python program to find numbers within a given range where every number is divisible by every digit it contains.
Next: Write a Python program to find the list with maximum and minimum length using lambda.

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Python: Tips of the Day

Returns all the elements of a list except the last one

Example:

def tips_initial(lst):
  return lst[0:-1]

print(tips_initial([1, 2, 3, 4]))

Output:

[1, 2, 3]