Python: Find the list with maximum and minimum length using lambda
Python Lambda: Exercise-26 with Solution
Write a Python program to find the list with maximum and minimum length using lambda.
Python Code :
def max_length_list(input_list): max_length = max(len(x) for x in input_list ) max_list = max(input_list, key = lambda i: len(i)) return(max_length, max_list) def min_length_list(input_list): min_length = min(len(x) for x in input_list ) min_list = min(input_list, key = lambda i: len(i)) return(min_length, min_list) list1 = [, [1, 3], [5, 7], [9, 11], [13, 15, 17]] print("Original list:") print(list1) print("\nList with maximum length of lists:") print(max_length_list(list1)) print("\nList with minimum length of lists:") print(min_length_list(list1))
Original list: [, [1, 3], [5, 7], [9, 11], [13, 15, 17]] List with maximum length of lists: (3, [13, 15, 17]) List with minimum length of lists: (1, )
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Previous: Write a Python program to create the next bigger number by rearranging the digits of a given number.
Next: Write a Python program to sort each sublist of strings in a given list of lists using lambda.
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Python: Cache results with decorators
There is a great way to cache functions with decorators in Python. Caching will help save time and precious resources when there is an expensive function at hand.
Implementation is easy, just import lru_cache from functools library and decorate your function using @lru_cache.
from functools import lru_cache @lru_cache(maxsize=None) def fibo(a): if a <= 1: return a else: return fibo(a-1) + fibo(a-2) for i in range(20): print(fibo(i), end="|") print("\n\n", fibo.cache_info())
0|1|1|2|3|5|8|13|21|34|55|89|144|233|377|610|987|1597|2584|4181| CacheInfo(hits=36, misses=20, maxsize=None, currsize=20)
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