﻿ Python: Square and cube every number in a given list of integers using Lambda - w3resource

Python: Square and cube every number in a given list of integers using Lambda

Python Lambda: Exercise-6 with Solution

Write a Python program to square and cube every number in a given list of integers using Lambda.

Sample Solution:

Python Code :

``````nums = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
print("Original list of integers:")
print(nums)
print("\nSquare every number of the said list:")
square_nums = list(map(lambda x: x ** 2, nums))
print(square_nums)
print("\nCube every number of the said list:")
cube_nums = list(map(lambda x: x ** 3, nums))
print(cube_nums)
``````

Sample Output:

```Original list of integers:
[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]

Square every number of the said list:
[1, 4, 9, 16, 25, 36, 49, 64, 81, 100]

Cube every number of the said list:
[1, 8, 27, 64, 125, 216, 343, 512, 729, 1000]
```

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Python: Tips of the Day

Python: Cache results with decorators

There is a great way to cache functions with decorators in Python. Caching will help save time and precious resources when there is an expensive function at hand.

Implementation is easy, just import lru_cache from functools library and decorate your function using @lru_cache.

```from functools import lru_cache

@lru_cache(maxsize=None)
def fibo(a):
if a <= 1:
return a
else:
return fibo(a-1) + fibo(a-2)

for i in range(20):
print(fibo(i), end="|")

print("\n\n", fibo.cache_info())
```

Output:

```0|1|1|2|3|5|8|13|21|34|55|89|144|233|377|610|987|1597|2584|4181|

CacheInfo(hits=36, misses=20, maxsize=None, currsize=20)```