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Python: Filter a list of integers using Lambda

Python Lambda: Exercise-5 with Solution

Write a Python program to filter a list of integers using Lambda.

Sample Solution:

Python Code :

nums = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
print("Original list of integers:")
print(nums)
print("\nEven numbers from the said list:")
even_nums = list(filter(lambda x: x%2 == 0, nums))
print(even_nums)
print("\nOdd numbers from the said list:")
odd_nums = list(filter(lambda x: x%2 != 0, nums))
print(odd_nums)

Sample Output:

Original list of integers:
[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]

Even numbers from the said list:
[2, 4, 6, 8, 10]

Odd numbers from the said list:
[1, 3, 5, 7, 9]

Visualize Python code execution:

The following tool visualize what the computer is doing step-by-step as it executes the said program:


Test for a single number:

Python Code :

print((lambda x: (x % 2 and 'Odd number' or 'Even number'))(5))
print((lambda x: (x % 2 and 'Odd number' or 'Even number'))(8))

Sample Output:

Odd number
Even number

Python Code Editor:

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Previous: Write a Python program to sort a list of dictionaries using Lambda.
Next: Write a Python program to square and cube every number in a given list of integers using Lambda.

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Python: Tips of the Day

Python: Cache results with decorators

There is a great way to cache functions with decorators in Python. Caching will help save time and precious resources when there is an expensive function at hand.

Implementation is easy, just import lru_cache from functools library and decorate your function using @lru_cache.

from functools import lru_cache

@lru_cache(maxsize=None)
def fibo(a):
    if a <= 1:
        return a
    else:
        return fibo(a-1) + fibo(a-2)

for i in range(20):
    print(fibo(i), end="|")

print("\n\n", fibo.cache_info())

Output:

0|1|1|2|3|5|8|13|21|34|55|89|144|233|377|610|987|1597|2584|4181|

 CacheInfo(hits=36, misses=20, maxsize=None, currsize=20)