﻿ Python: Extract the nth element from a given list of tuples - w3resource

# Python: Extract the nth element from a given list of tuples

## Python List: Exercise - 114 with Solution

Write a Python program to extract the nth element from a given list of tuples.

Sample Solution:

Python Code:

``````def extract_nth_element(test_list, n):
result = [x[n] for x in test_list]
return result

students = [('Greyson Fulton', 98, 99), ('Brady Kent', 97, 96), ('Wyatt Knott', 91, 94), ('Beau Turnbull', 94, 98)]
print ("Original list:")
print(students)
n = 0
print("\nExtract nth element ( n =",n,") from the said list of tuples:")
print(extract_nth_element(students, n))

n = 2
print("\nExtract nth element ( n =",n,") from the said list of tuples:")
print(extract_nth_element(students, n))
```
```

Sample Output:

```Original list:
[('Greyson Fulton', 98, 99), ('Brady Kent', 97, 96), ('Wyatt Knott', 91, 94), ('Beau Turnbull', 94, 98)]

Extract nth element ( n = 0 ) from the said list of tuples:
['Greyson Fulton', 'Brady Kent', 'Wyatt Knott', 'Beau Turnbull']

Extract nth element ( n = 2 ) from the said list of tuples:
[99, 96, 94, 98]
```

Pictorial Presentation: Flowchart: ## Visualize Python code execution:

The following tool visualize what the computer is doing step-by-step as it executes the said program:

Python Code Editor:

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﻿

## Python: Tips of the Day

Given a predicate function, fn, and a prop string, this curried function will then take an object to inspect by calling the property and passing it to the predicate:

Example:

```def tips_check_prop(fn, prop):
return lambda obj: fn(obj[prop])
check_age = tips_check_prop(lambda x: x >= 25, 'age')
user = {'name': 'Owen', 'age': 25}

print(check_age(user))
```

Output:

```True
```

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