Python: Find the difference between elements (n+1th – nth) of a given list of numeric values
Python List: Exercise - 118 with Solution
Write a Python program to find the difference between elements (n+1th – nth) of a given list of numeric values.
Sample Solution:
Python Code:
def elements_difference(nums):
result = [j-i for i, j in zip(nums[:-1], nums[1:])]
return result
nums1 = [1,2,3,4,5,6,7,8,9,10]
nums2 = [2,4,6,8]
print("Original list:")
print(nums1)
print("\nDfference between elements (n+1th – nth) of the said list :")
print(elements_difference(nums1))
print("\nOriginal list:")
print(nums2)
print("\nDfference between elements (n+1th – nth) of the said list :")
print(elements_difference(nums2))
Sample Output:
Original list: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10] Dfference between elements (n+1th – nth) of the said list : [1, 1, 1, 1, 1, 1, 1, 1, 1] Original list: [2, 4, 6, 8] Dfference between elements (n+1th – nth) of the said list : [2, 2, 2]
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Python: Tips of the Day
Returns True if the provided function returns True for every element in the list, False otherwise:
Example:
def tips_every(lst, fn=lambda x: x): return all(map(fn, lst)) print(tips_every([2, 4, 3], lambda x: x > 1)) print(tips_every([1, 2, 3]))
Output:
True True
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