w3resource

Python: Check if a substring presents in a given list of string values

Python List: Exercise - 119 with Solution

Write a Python program to check if a substring appears in a given list of string values.

Sample Solution:

Python Code:

def find_substring(str1, sub_str):
   if any(sub_str in s for s in str1):
       return True
   return False

colors = ["red", "black", "white", "green", "orange"]
print("Original list:")
print(colors)
sub_str = "ack"
print("Substring to search:")
print(sub_str)
print("Check if a substring presents in the said list of string values:")
print(find_substring(colors, sub_str))
sub_str = "abc"
print("Substring to search:")
print(sub_str)
print("Check if a substring presents in the said list of string values:")
print(find_substring(colors, sub_str))

Sample Output:

Original list:
['red', 'black', 'white', 'green', 'orange']
Substring to search:
ack
Check if a substring presents in the said list of string values:
True
Substring to search:
abc
Check if a substring presents in the said list of string values:
False

Pictorial Presentation:

Python List: Check if a substring presents in a given list of string values.

Flowchart:

Flowchart: Check if a substring presents in a given list of string values.

Visualize Python code execution:

The following tool visualize what the computer is doing step-by-step as it executes the said program:


Python Code Editor:

Have another way to solve this solution? Contribute your code (and comments) through Disqus.

Previous: Write a Python program to find the difference between elements (n+1th – nth) of a given list of numeric values.
Next: Write a Python program to create a list taking alternate elements from a given list.

What is the difficulty level of this exercise?

Test your Programming skills with w3resource's quiz.



Follow us on Facebook and Twitter for latest update.

Python: Tips of the Day

Returns True if the provided function returns True for every element in the list, False otherwise:

Example:

def tips_every(lst, fn=lambda x: x):
  return all(map(fn, lst))

print(tips_every([2, 4, 3], lambda x: x > 1))
print(tips_every([1, 2, 3]))

Output:

True
True