Python: Create a list taking alternate elements from a given list
Python List: Exercise - 120 with Solution
Write a Python program to create a list taking alternate elements from a given list.
def alternate_elements(list_data): result= for item in list_data[::2]: result.append(item) return result colors = ["red", "black", "white", "green", "orange"] print("Original list:") print(colors) print("List with alternate elements from the said list:") print(alternate_elements(colors)) nums = [2,0,3,4,0,2,8,3,4,2] print("\nOriginal list:") print(nums) print("List with alternate elements from the said list:") print(alternate_elements(nums))
Original list: ['red', 'black', 'white', 'green', 'orange'] List with alternate elements from the said list: ['red', 'white', 'orange'] Original list: [2, 0, 3, 4, 0, 2, 8, 3, 4, 2] List with alternate elements from the said list: [2, 3, 0, 8, 4]
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Python: Tips of the Day
Returns True if the provided function returns True for every element in the list, False otherwise:
def tips_every(lst, fn=lambda x: x): return all(map(fn, lst)) print(tips_every([2, 4, 3], lambda x: x > 1)) print(tips_every([1, 2, 3]))
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