Python: Count the frequency of consecutive duplicate elements in a given list of numbers
Python List: Exercise - 131 with Solution
Write a Python program to count the frequency of consecutive duplicate elements in a given list of numbers.
Sample Solution:
Python Code:
def count_dups(nums):
element = []
freque = []
if not nums:
return element
running_count = 1
for i in range(len(nums)-1):
if nums[i] == nums[i+1]:
running_count += 1
else:
freque.append(running_count)
element.append(nums[i])
running_count = 1
freque.append(running_count)
element.append(nums[i+1])
return element,freque
nums = [1,2,2,2,4,4,4,5,5,5,5]
print("Original lists:")
print(nums)
print("\nConsecutive duplicate elements and their frequency:")
print(count_dups(nums))
Sample Output:
Original lists: [1, 2, 2, 2, 4, 4, 4, 5, 5, 5, 5] Consecutive duplicate elements and their frequency: ([1, 2, 4, 5], [1, 3, 3, 4])
Flowchart:

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Previous: Write a Python program to count the same pair in three given lists.
Next: Write a Python program to find all index positions of the maximum and minimum values in a given list of numbers.
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Python: Tips of the Day
Given a predicate function, fn, and a prop string, this curried function will then take an object to inspect by calling the property and passing it to the predicate:
Example:
def tips_check_prop(fn, prop): return lambda obj: fn(obj[prop]) check_age = tips_check_prop(lambda x: x >= 25, 'age') user = {'name': 'Owen', 'age': 25} print(check_age(user))
Output:
True
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