Python: Remove first specified number of elements from a given list satisfying a condition
Python List: Exercise - 160 with Solution
Write a Python program to remove the first specified number of elements from a given list satisfying a condition.
Remove the first 4 number of even numbers from the following list:
[3,10,4,7,5,7,8,3,3,4,5,9,3,4,9,8,5]
Output:
[3, 7, 5, 7, 3, 3, 5, 9, 3, 4, 9, 8, 5]
Sample Solution:
Python Code:
def condition_match(x):
return ((x % 2) == 0)
def remove_items_con(data, N):
ctr = 1
result = []
for x in data:
if ctr > N or not condition_match(x):
result.append(x)
else:
ctr = ctr + 1
return result
nums = [3,10,4,7,5,7,8,3,3,4,5,9,3,4,9,8,5]
N = 4
print("Original list:")
print(nums)
print("\nRemove first 4 even numbers from the said list:")
print(remove_items_con(nums, N))
Sample Output:
Original list: [3, 10, 4, 7, 5, 7, 8, 3, 3, 4, 5, 9, 3, 4, 9, 8, 5] Remove first 4 even numbers from the said list: [3, 7, 5, 7, 3, 3, 5, 9, 3, 4, 9, 8, 5]
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Previous: Write a Python program to append the same value /a list multiple times to a list/list-of-lists.
Next: Write a Python program to check if a given list is strictly increasing or not. Moreover, If removing only one element from the list results in a strictly increasing list, we still consider the list true.
What is the difficulty level of this exercise?
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Python: Tips of the Day
Returns True if the provided function returns True for every element in the list, False otherwise:
Example:
def tips_every(lst, fn=lambda x: x): return all(map(fn, lst)) print(tips_every([2, 4, 3], lambda x: x > 1)) print(tips_every([1, 2, 3]))
Output:
True True
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