Python: Check if a given list is strictly increasing or not
Python List: Exercise - 161 with Solution
Write a Python program to check if a given list increases strictly. Moreover, if removing only one element from the list results in a strictly increasing list, we still consider the list true.
Sample Solution:
Python Code:
# Source: https://bit.ly/3qZqcwm
def almost_increasing_sequence(sequence):
if len(sequence) < 3:
return True
a, b, *sequence = sequence
skipped = 0
for c in sequence:
if a < b < c: # XXX
a, b = b, c
continue
elif b < c: # !XX
a, b = b, c
elif a < c: # X!X
a, b = a, c
skipped += 1
if skipped == 2:
return False
return a < b
print(almost_increasing_sequence([]))
print(almost_increasing_sequence([1]))
print(almost_increasing_sequence([1, 2]))
print(almost_increasing_sequence([1, 2, 3]))
print(almost_increasing_sequence([3, 1, 2]))
print(almost_increasing_sequence([1, 2, 3, 0, 4, 5, 6]))
print(almost_increasing_sequence([1, 2, 3, 0]))
print(almost_increasing_sequence([1, 2, 0, 3]))
print(almost_increasing_sequence([10, 1, 2, 3, 4, 5]))
print(almost_increasing_sequence([1, 2, 10, 3, 4]))
print(almost_increasing_sequence([1, 2, 3, 12, 4, 5]))
print(almost_increasing_sequence([3, 2, 1]))
print(almost_increasing_sequence([1, 2, 0, -1]))
print(almost_increasing_sequence([5, 6, 1, 2]))
print(almost_increasing_sequence([1, 2, 3, 0, -1]))
print(almost_increasing_sequence([10, 11, 12, 2, 3, 4, 5]))
Sample Output:
True True True True True True True True True True True False False False False False
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Previous: Write a Python program to remove first specified number of elements from a given list satisfying a condition.
Next: Write a Python program to find the last occurrence of a specified item in a given list.
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Python: Tips of the Day
Returns True if the provided function returns True for every element in the list, False otherwise:
Example:
def tips_every(lst, fn=lambda x: x): return all(map(fn, lst)) print(tips_every([2, 4, 3], lambda x: x > 1)) print(tips_every([1, 2, 3]))
Output:
True True
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