Python: Chunk a given list into n smaller lists
Python List: Exercise - 233 with Solution
Write a Python program to chunk a given list into n smaller lists.
- Use math.ceil() and len() to get the size of each chunk.
- Use list() and range() to create a new list of size n.
- Use map() to map each element of the new list to a chunk the length of size.
- If the original list can't be split evenly, the final chunk will contain the remaining elements.
Sample Solution:
Python Code:
from math import ceil
def chunk_list_into_n(nums, n):
size = ceil(len(nums) / n)
return list(
map(lambda x: nums[x * size:x * size + size],
list(range(n)))
)
print(chunk_list_into_n([1, 2, 3, 4, 5, 6, 7], 4))
Sample Output:
[[1, 2], [3, 4], [5, 6], [7]]
Flowchart:

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Python: Tips of the Day
Returns True if the provided function returns True for every element in the list, False otherwise:
Example:
def tips_every(lst, fn=lambda x: x): return all(map(fn, lst)) print(tips_every([2, 4, 3], lambda x: x > 1)) print(tips_every([1, 2, 3]))
Output:
True True
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