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Python: Find the items that are parity outliers in a given list

Python List: Exercise - 236 with Solution

Write a Python program to find items that are parity outliers in a given list.

  • Use collections.Counter with a list comprehension to count even and odd values in the list.
  • Use collections.Counter.most_common() to get the most common parity.
  • Use a list comprehension to find all elements that do not match the most common parity.

Sample Solution:

Python Code:

from collections import Counter
def find_parity_outliers(nums):
  return [
    x for x in nums
    if x % 2 != Counter([n % 2 for n in nums]).most_common()[0][0]
  ] 
print(find_parity_outliers([1, 2, 3, 4, 6]))  
print(find_parity_outliers([1, 2, 3, 4, 5, 6, 7]))

Sample Output: 

[1, 3]
[2, 4, 6]

Flowchart:

Flowchart: Find the items that are parity outliers in a given list.

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Previous: Write a Python program to find the index of the last element in the given list that satisfies the provided testing function.
Next: Write a Python program to convert a given list of dictionaries into a list of values corresponding to the specified key.

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Python: Tips of the Day

Creates a list of elements, grouped based on the position in the original lists:

Example:

def tips_zip(*args, fill_value=None):
  	max_length = max([len(lst) for lst in args])
 	 result = []
  	for i in range(max_length):
   	 result.append([
      args[k][i] if i < len(args[k]) else fillvalue for k in range(len(args))
   	 ])
 	 return result
print(tips_zip(['a', 'b'], [1, 2], [True, False]))
print(tips_zip(['a'], [1, 2], [True, False]))
print(tips_zip(['a'], [1, 2], [True, False], fill_value = '1'))

Output:

[['a', 1, True], ['b', 2, False]]
[['a', 1, True], [None, 2, False]]
[['a', 1, True], ['1', 2, False]]