Python: Find the items that are parity outliers in a given list
Python List: Exercise - 236 with Solution
Write a Python program to find items that are parity outliers in a given list.
- Use collections.Counter with a list comprehension to count even and odd values in the list.
- Use collections.Counter.most_common() to get the most common parity.
- Use a list comprehension to find all elements that do not match the most common parity.
Sample Solution:
Python Code:
from collections import Counter
def find_parity_outliers(nums):
return [
x for x in nums
if x % 2 != Counter([n % 2 for n in nums]).most_common()[0][0]
]
print(find_parity_outliers([1, 2, 3, 4, 6]))
print(find_parity_outliers([1, 2, 3, 4, 5, 6, 7]))
Sample Output:
[1, 3] [2, 4, 6]
Flowchart:

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Previous: Write a Python program to find the index of the last element in the given list that satisfies the provided testing function.
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Python: Tips of the Day
Creates a list of elements, grouped based on the position in the original lists:
Example:
def tips_zip(*args, fill_value=None): max_length = max([len(lst) for lst in args]) result = [] for i in range(max_length): result.append([ args[k][i] if i < len(args[k]) else fillvalue for k in range(len(args)) ]) return result print(tips_zip(['a', 'b'], [1, 2], [True, False])) print(tips_zip(['a'], [1, 2], [True, False])) print(tips_zip(['a'], [1, 2], [True, False], fill_value = '1'))
Output:
[['a', 1, True], ['b', 2, False]] [['a', 1, True], [None, 2, False]] [['a', 1, True], ['1', 2, False]]
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