﻿ Python: Find the items that are parity outliers in a given list - w3resource

# Python: Find the items that are parity outliers in a given list

## Python List: Exercise - 236 with Solution

Write a Python program to find items that are parity outliers in a given list.

• Use collections.Counter with a list comprehension to count even and odd values in the list.
• Use collections.Counter.most_common() to get the most common parity.
• Use a list comprehension to find all elements that do not match the most common parity.

Sample Solution:

Python Code:

``````from collections import Counter
def find_parity_outliers(nums):
return [
x for x in nums
if x % 2 != Counter([n % 2 for n in nums]).most_common()
]
print(find_parity_outliers([1, 2, 3, 4, 6]))
print(find_parity_outliers([1, 2, 3, 4, 5, 6, 7]))
```
```

Sample Output:

```[1, 3]
[2, 4, 6]
```

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## Python: Tips of the Day

Creates a list of elements, grouped based on the position in the original lists:

Example:

```def tips_zip(*args, fill_value=None):
max_length = max([len(lst) for lst in args])
result = []
for i in range(max_length):
result.append([
args[k][i] if i < len(args[k]) else fillvalue for k in range(len(args))
])
return result
print(tips_zip(['a', 'b'], [1, 2], [True, False]))
print(tips_zip(['a'], [1, 2], [True, False]))
print(tips_zip(['a'], [1, 2], [True, False], fill_value = '1'))
```

Output:

```[['a', 1, True], ['b', 2, False]]
[['a', 1, True], [None, 2, False]]
[['a', 1, True], ['1', 2, False]]
```