Python: Find the items that are parity outliers in a given list
Python List: Exercise - 236 with Solution
Write a Python program to find items that are parity outliers in a given list.
- Use collections.Counter with a list comprehension to count even and odd values in the list.
- Use collections.Counter.most_common() to get the most common parity.
- Use a list comprehension to find all elements that do not match the most common parity.
from collections import Counter def find_parity_outliers(nums): return [ x for x in nums if x % 2 != Counter([n % 2 for n in nums]).most_common() ] print(find_parity_outliers([1, 2, 3, 4, 6])) print(find_parity_outliers([1, 2, 3, 4, 5, 6, 7]))
[1, 3] [2, 4, 6]
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Python: Tips of the Day
Creates a list of elements, grouped based on the position in the original lists:
def tips_zip(*args, fill_value=None): max_length = max([len(lst) for lst in args]) result =  for i in range(max_length): result.append([ args[k][i] if i < len(args[k]) else fillvalue for k in range(len(args)) ]) return result print(tips_zip(['a', 'b'], [1, 2], [True, False])) print(tips_zip(['a'], [1, 2], [True, False])) print(tips_zip(['a'], [1, 2], [True, False], fill_value = '1'))
[['a', 1, True], ['b', 2, False]] [['a', 1, True], [None, 2, False]] [['a', 1, True], ['1', 2, False]]
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