﻿ Python: Convert a list of dictionaries into a list of values corresponding to the specified key - w3resource

# Python: Convert a list of dictionaries into a list of values corresponding to the specified key

## Python List: Exercise - 237 with Solution

Write a Python program to convert a given list of dictionaries into a list of values corresponding to the specified key.

Use a list comprehension and dict.get() to get the value of key for each dictionary in lst.

Sample Solution:

Python Code:

``````def pluck(lst, key):
return [x.get(key) for x in lst]

simpsons = [
{ 'name': 'Areeba', 'age': 8 },
{ 'name': 'Zachariah', 'age': 36 },
{ 'name': 'Caspar', 'age': 34 },
{ 'name': 'Presley', 'age': 10 }
]
print(pluck(simpsons, 'age'))
```
```

Sample Output:

```[8, 36, 34, 10]
```

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Python Code Editor:

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## Python: Tips of the Day

Creates a list of elements, grouped based on the position in the original lists:

Example:

```def tips_zip(*args, fill_value=None):
max_length = max([len(lst) for lst in args])
result = []
for i in range(max_length):
result.append([
args[k][i] if i < len(args[k]) else fillvalue for k in range(len(args))
])
return result
print(tips_zip(['a', 'b'], [1, 2], [True, False]))
print(tips_zip(['a'], [1, 2], [True, False]))
print(tips_zip(['a'], [1, 2], [True, False], fill_value = '1'))
```

Output:

```[['a', 1, True], ['b', 2, False]]
[['a', 1, True], [None, 2, False]]
[['a', 1, True], ['1', 2, False]]
```