Python: Check if two lists contain the same elements regardless of order
Python List: Exercise - 257 with Solution
Write a Python program to check if two given lists contain the same elements regardless of order.
- Use set() on the combination of both lists to find the unique values.
- Iterate over them with a for loop comparing the count() of each unique value in each list.
- Return False if the counts do not match for any element, True otherwise.
Sample Solution:
Python Code:
def check_same_contents(nums1, nums2):
for x in set(nums1 + nums2):
if nums1.count(x) != nums2.count(x):
return False
return True
nums1 = [1, 2, 4]
nums2 = [2, 4, 1]
print("Original list elements:")
print(nums1)
print(nums2)
print("\nCheck two said lists contain the same elements regardless of order!")
print(check_same_contents(nums1, nums2))
nums1 = [1, 2, 3]
nums2 = [1, 2, 3]
print("\nOriginal list elements:")
print(nums1)
print(nums2)
print("\nCheck two said lists contain the same elements regardless of order!")
print(check_same_contents(nums1, nums2))
nums1 = [1, 2, 3]
nums2 = [1, 2, 4]
print("\nOriginal list elements:")
print(nums1)
print(nums2)
print("\nCheck two said lists contain the same elements regardless of order!")
print(check_same_contents(nums1, nums2))
Sample Output:
Original list elements: [1, 2, 4] [2, 4, 1] Check two said lists contain the same elements regardless of order! True Original list elements: [1, 2, 3] [1, 2, 3] Check two said lists contain the same elements regardless of order! True Original list elements: [1, 2, 3] [1, 2, 4] Check two said lists contain the same elements regardless of order! False
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