﻿ Python: Find the second smallest number in a list - w3resource

# Python: Find the second smallest number in a list

## Python List: Exercise - 27 with Solution

Write a Python program to find the second smallest number in a list.

Example - 1 :

Example - 2 :

Example - 3 :

Example - 4 :

Sample Solution:-

Python Code:

``````def second_smallest(numbers):
if (len(numbers)<2):
return
if ((len(numbers)==2)  and (numbers[0] == numbers[1]) ):
return
dup_items = set()
uniq_items = []
for x in numbers:
if x not in dup_items:
uniq_items.append(x)
uniq_items.sort()
return  uniq_items[1]

print(second_smallest([1, 2, -8, -2, 0, -2]))
print(second_smallest([1, 1, 0, 0, 2, -2, -2]))
print(second_smallest([1, 1, 1, 0, 0, 0, 2, -2, -2]))
print(second_smallest([2,2]))
print(second_smallest([2]))
```
```

Sample Output:

```-2
0
0
None
None
```

Flowchart:

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Python Code Editor:

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## Python: Tips of the Day

```print(2_000_000)
```2000000