﻿ Python: Find the second largest number in a list - w3resource # Python: Find the second largest number in a list

## Python List: Exercise - 28 with Solution

Write a Python program to find the second largest number in a list.

Example - 1 : Example - 2 : Example - 3 : Example - 4 : Sample Solution:-

Python Code:

``````def second_largest(numbers):
if (len(numbers)<2):
return
if ((len(numbers)==2)  and (numbers == numbers) ):
return
dup_items = set()
uniq_items = []
for x in numbers:
if x not in dup_items:
uniq_items.append(x)
uniq_items.sort()
return  uniq_items[-2]
print(second_largest([1,2,3,4,4]))
print(second_largest([1, 1, 1, 0, 0, 0, 2, -2, -2]))
print(second_largest([2,2]))
print(second_largest())
```
```

Sample Output:

```3
1
None
None
```

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﻿

## Python: Tips of the Day

Python: The Zip() Function

```>>> students = ('John', 'Mary', 'Mike')
>>> ages = (15, 17, 16)
>>> scores = (90, 88, 82, 17, 14)
>>> for student, age, score in zip(students, ages, scores):
...     print(f'{student}, age: {age}, score: {score}')
...
John, age: 15, score: 90
Mary, age: 17, score: 88
Mike, age: 16, score: 82
>>> zipped = zip(students, ages, scores)
>>> a, b, c = zip(*zipped)
>>> print(b)
(15, 17, 16)
```