﻿ Python: Find the second largest number in a list - w3resource

# Python: Find the second largest number in a list

## Python List: Exercise - 28 with Solution

Write a Python program to find the second largest number in a list.

Example - 1 :

Example - 2 :

Example - 3 :

Example - 4 :

Sample Solution:-

Python Code:

``````def second_largest(numbers):
if (len(numbers)<2):
return
if ((len(numbers)==2)  and (numbers[0] == numbers[1]) ):
return
dup_items = set()
uniq_items = []
for x in numbers:
if x not in dup_items:
uniq_items.append(x)
uniq_items.sort()
return  uniq_items[-2]
print(second_largest([1,2,3,4,4]))
print(second_largest([1, 1, 1, 0, 0, 0, 2, -2, -2]))
print(second_largest([2,2]))
print(second_largest([1]))
```
```

Sample Output:

```3
1
None
None
```

Flowchart:

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## Python: Tips of the Day

Floor Division:

When we speak of division we normally mean (/) float division operator, this will give a precise result in float format with decimals.

For a rounded integer result there is (//) floor division operator in Python. Floor division will only give integer results that are round numbers.

```print(1000 // 300)
print(1000 / 300)```

Output:

```3
3.3333333333333335```