# Python: Check whether a list contains a sublist

## Python List: Exercise - 32 with Solution

Write a Python program to check whether a list contains a sublist.

**Sample Solution:**

**Python Code:**

```
# Define a function named 'is_Sublist' that checks if list 's' is a sublist of list 'l'
def is_Sublist(l, s):
sub_set = False # Initialize a flag 'sub_set' to indicate whether 's' is a sublist of 'l
# Check if 's' is an empty list; in this case, 's' is a sublist of any list
if s == []:
sub_set = True
# Check if 's' is equal to 'l'; if so, 's' is a sublist of 'l
elif s == l:
sub_set = True
# Check if the length of 's' is greater than the length of 'l'; 's' cannot be a sublist in this case
elif len(s) > len(l):
sub_set = False
else:
# Iterate through the elements of 'l'
for i in range(len(l)):
# Check if the current element in 'l' matches the first element in 's'
if l[i] == s[0]:
n = 1
while (n < len(s)) and (l[i + n] == s[n]):
n += 1
# If 'n' equals the length of 's', 's' is a sublist of 'l
if n == len(s):
sub_set = True
# Return the value of 'sub_set,' which indicates whether 's' is a sublist of 'l
return sub_set
# Define list 'a,' 'b,' and 'c'
a = [2, 4, 3, 5, 7]
b = [4, 3]
c = [3, 7]
# Check if 'b' is a sublist of 'a' and print the result
print(is_Sublist(a, b))
# Check if 'c' is a sublist of 'a' and print the result
print(is_Sublist(a, c))
```

Sample Output:

True False

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