Python: Generate all sublists of a list
Python List: Exercise - 33 with Solution
Write a Python program to generate all sublists of a list.

Sample Solution:-
Python Code:
from itertools import combinations
def sub_lists(my_list):
subs = []
for i in range(0, len(my_list)+1):
temp = [list(x) for x in combinations(my_list, i)]
if len(temp)>0:
subs.extend(temp)
return subs
l1 = [10, 20, 30, 40]
l2 = ['X', 'Y', 'Z']
print("Original list:")
print(l1)
print("S")
print(sub_lists(l1))
print("Sublists of the said list:")
print(sub_lists(l1))
print("\nOriginal list:")
print(l2)
print("Sublists of the said list:")
print(sub_lists(l2))
Sample Output:
Original list: [10, 20, 30, 40] S [[], [10], [20], [30], [40], [10, 20], [10, 30], [10, 40], [20, 30], [20, 40], [30, 40], [10, 20, 30], [10, 20, 40], [10, 30, 40], [20, 30, 40], [10, 20, 30, 40]] Sublists of the said list: [[], [10], [20], [30], [40], [10, 20], [10, 30], [10, 40], [20, 30], [20, 40], [30, 40], [10, 20, 30], [10, 20, 40], [10, 30, 40], [20, 30, 40], [10, 20, 30, 40]] Original list: ['X', 'Y', 'Z'] Sublists of the said list: [[], ['X'], ['Y'], ['Z'], ['X', 'Y'], ['X', 'Z'], ['Y', 'Z'], ['X', 'Y', 'Z']]
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Python: Tips of the Day
Creates a list of elements, grouped based on the position in the original lists:
Example:
def tips_zip(*args, fill_value=None): max_length = max([len(lst) for lst in args]) result = [] for i in range(max_length): result.append([ args[k][i] if i < len(args[k]) else fillvalue for k in range(len(args)) ]) return result print(tips_zip(['a', 'b'], [1, 2], [True, False])) print(tips_zip(['a'], [1, 2], [True, False])) print(tips_zip(['a'], [1, 2], [True, False], fill_value = '1'))
Output:
[['a', 1, True], ['b', 2, False]] [['a', 1, True], [None, 2, False]] [['a', 1, True], ['1', 2, False]]
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