Python: Count the number of strings where the string length is 2 or more and the first and last character are same from a given list of strings
Python List: Exercise-5 with Solution
Write a Python program to count the number of strings from a given list of strings. The string length is 2 or more and the first and last characters are the same.
Sample Solution:-
Python Code:
def match_words(words):
ctr = 0
for word in words:
if len(word) > 1 and word[0] == word[-1]:
ctr += 1
return ctr
print(match_words(['abc', 'xyz', 'aba', '1221']))
Sample Output:
2
Flowchart:

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Python: Tips of the Day
Creates a list of elements, grouped based on the position in the original lists:
Example:
def tips_zip(*args, fill_value=None): max_length = max([len(lst) for lst in args]) result = [] for i in range(max_length): result.append([ args[k][i] if i < len(args[k]) else fillvalue for k in range(len(args)) ]) return result print(tips_zip(['a', 'b'], [1, 2], [True, False])) print(tips_zip(['a'], [1, 2], [True, False])) print(tips_zip(['a'], [1, 2], [True, False], fill_value = '1'))
Output:
[['a', 1, True], ['b', 2, False]] [['a', 1, True], [None, 2, False]] [['a', 1, True], ['1', 2, False]]
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