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Python: Count the number of strings where the string length is 2 or more and the first and last character are same from a given list of strings

Python List: Exercise-5 with Solution

Write a Python program to count the number of strings from a given list of strings. The string length is 2 or more and the first and last characters are the same.

Sample Solution:-

Python Code:

def match_words(words):
  ctr = 0

  for word in words:
    if len(word) > 1 and word[0] == word[-1]:
      ctr += 1
  return ctr

print(match_words(['abc', 'xyz', 'aba', '1221']))

Sample Output: 

2

Flowchart:

Flowchart: Count the number of strings where the string length is 2 or more and the first and last character are same from a given list of strings

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Python: Tips of the Day

Creates a list of elements, grouped based on the position in the original lists:

Example:

def tips_zip(*args, fill_value=None):
  	max_length = max([len(lst) for lst in args])
 	 result = []
  	for i in range(max_length):
   	 result.append([
      args[k][i] if i < len(args[k]) else fillvalue for k in range(len(args))
   	 ])
 	 return result
print(tips_zip(['a', 'b'], [1, 2], [True, False]))
print(tips_zip(['a'], [1, 2], [True, False]))
print(tips_zip(['a'], [1, 2], [True, False], fill_value = '1'))

Output:

[['a', 1, True], ['b', 2, False]]
[['a', 1, True], [None, 2, False]]
[['a', 1, True], ['1', 2, False]]