Python: Get the smallest number from a list

Python List: Exercise-4 with Solution

Write a Python program to get the smallest number from a list.

Pictorial Presentation:

Sample Solution:

Python Code:

def smallest_num_in_list( list ):
    min = list[ 0 ]
    for a in list:
        if a < min:
            min = a
    return min
print(smallest_num_in_list([1, 2, -8, 0]))

Sample Output:

-8 

Explanation:

In the above exercise -

def smallest_num_in_list( list ):  -> This code defines a function “smallest_num_in_list()” that takes a single argument list. This function will be used to find the smallest number in the list.

min = list[ 0 ]  -> We assume the list is not empty. This line initializes a variable called 'min' to the first element of the list.

for a in list:  -> This line starts a loop that will iterate over each element in the list, one at a time. The loop variable 'a' will take on the value of each element in the list during each iteration of the loop.

if a < min:
   min = a

The above line compares the current element 'a' to the current smallest min. If 'a' is less than 'min', 'min' is updated to equal 'a'. After iterating through the entire list, ‘min’ will hold the value of the smallest number in the list.

return min  -> This line returns the final value of the 'min' variable after the loop has finished.

print(smallest_num_in_list([1, 2, -8, 0])) -> This line calls the 'smallest_num_in_list()' function and passes in the list [1, 2, -8, 0]. Finally print() function prints the resulting smallest value.

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