Python: Get the largest number from a list

Python List: Exercise-3 with Solution

Write a Python program to get the largest number from a list.

Pictorial Presentation:

Python: Get the largest number from a list

Sample Solution:

Python Code:

def max_num_in_list( list ):
    max = list[ 0 ]
    for a in list:
        if a > max:
            max = a
    return max
print(max_num_in_list([1, 2, -8, 0]))

Sample Output:



In the above code -

def max_num_in_list( list ):  -> This code defines a function called max_num_in_list that takes a single argument list. This function will be used to find the maximum number in the list.

max = list[ 0 ]  -> We assume the list is not empty. This line initializes a variable called max to the first element of the list.

for a in list:  -> This line starts a loop that will iterate over each element in the list, one at a time. The loop variable 'a' will take on the value of each element in the list during each iteration of the loop.

if a > max: 
     max = a

The above line compares the current element 'a' to the current maximum max. If 'a' is greater than 'max', 'max' is updated to equal 'a'. After iterating through the entire list, 'max' will hold the value of the largest number in the list.

return max -> This line returns the final value of the ‘max’ variable after the loop has finished.

print(max_num_in_list([1, 2, -8, 0])) -> This line calls the ‘max_num_in_list()’ function and passes in the list [1, 2, -8, 0]. Finally print() function prints the resulting maximum value.


Flowchart: Get the largest number from a list

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Python: Tips of the Day

Given a predicate function, fn, and a prop string, this curried function will then take an object to inspect by calling the property and passing it to the predicate:


def tips_check_prop(fn, prop):
  return lambda obj: fn(obj[prop])
check_age = tips_check_prop(lambda x: x >= 25, 'age')
user = {'name': 'Owen', 'age': 25}





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